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Arlecino [84]
3 years ago
12

During nuclear fission, great amounts of energy are produced from____. A. particle accelerators B. tremendous amounts of mass C.

a series of chemical reactions D. very small amounts of mass.
Chemistry
2 answers:
LekaFEV [45]3 years ago
6 0

Answer: Option (C) is the correct answer.

Explanation:

Nuclear fission is a process in which a large nucleus splits into two or more small nuclei.

For example, ^{239}_{94}Pu \rightarrow ^{134}_{54}Xe + ^{103}_{40}Zr + 3^{1}_{0}n

The neutrons produced in the reaction will again react with plutonium and thus it will form a series of chain reaction. As a result, there will be continuous reaction of neutrons with the plutonium atom thus, it will create a great amount of energy.

Thus, we can conclude that during nuclear fission, great amounts of energy are produced from a series of chemical reactions.

Phoenix [80]3 years ago
3 0
During nuclear fission, great amounts of energy are produced from____.

Answer: Out of all the options presented above, the one that completes the statement and makes it true, is answer choice D) very small amounts of mass. Nuclear fission power does not produce carbon and also produces 12% of the world's power.

I hope it helps, Regards.
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Explanation:

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<em>2KOH + H₂SO₄ → K₂SO₄ + 2H₂O.</em>

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Calculate the molarity of H3PO4 when you added 57.3 g into 3,820 mL of water
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0.153M

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5 0
3 years ago
What volume does 2.25g of nitrogen gas, N2, occupy at 273 Celsius and 1.02 atm​
kotykmax [81]
<h2><u>Answer:</u></h2>

0.126 Liters

<h2><u>Explanation:</u></h2>

V = mRT / mmP

First, convert the 2.25g of Nitrogen gas into moles. (m in the equation above)

2.25g x 1 mole / 28.0g = 0.08036 moles = m

28.0g = mm

Next, convert the 273 Celsius into Kelvin. (T in the equation above)

273 Celsius + 273.15 = 546.15K = T

R = 0.08206L*atm/mol*K

(Quick Note: The R changes depending on the Pressure Unit so do not use this number every time.)

Now, plug everything into the equation.

V = (0.08036)(0.08206)(546.15)/(28.0)(1.02)

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