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zloy xaker [14]
2 years ago
9

the mass of a single potassium atom is 6.50×10-23 grams. How many potassium atoms would there be in 114 milligrams of potassium?

Chemistry
1 answer:
Nataly [62]2 years ago
8 0

Answer:LOL

42

Explanation:

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How does a balanced chemical equation demonstrate conservation of mass?
Mariulka [41]

Answer:

A balanced chemical equation will demonstrate the law of conservation of mass because the amount of elements on one side (reactants) will equal the amount of elements on the other side (products).

Explanation:

CH₄ + 4Cl₂ -> CCl₄ + 4HCl

Reactants:

1 C

4 H

8 Cl

Products:

1 C

4 H

8 Cl

6 0
2 years ago
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Briefly describe the movement of water through the water cycle
kotegsom [21]

1) Evaporization is phase change process in which the water changes from a liquid to a gas (water vapor). Solar radiation is the source of energy for evaporation.

2) Condensation is phase change process in which the water changes from a gas to a liquid, the vapor becomes a cloud.

3) Precipitation is falling of the condensed water vapor as rain, snow, fog drip.

The water cycle (hydrological cycle) is the continuous movement of water all around the Earth.


8 0
3 years ago
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How many grams of potassium nitrate (KNO3) would form if 2.25 liters of a 1.50 molar lead nitrate Pb(NO3)2 solution reacts with
fgiga [73]
I know that the answer is 639 g
4 0
3 years ago
You have 0.14 moles of sodium chloride (NaCl). How many grams do you have? ( 1 mole of NaCl = 58 grams NaCl) *
Step2247 [10]

Answer:

Option D is correct = 8.12 grams of NaCl

Explanation:

Given data:

Moles of sodium chloride = 0.14 mol

Mass of sodium chloride = ?

Solution:

Formula:

Number of moles = mass of NaCl / Molar mass of NaCl

Molar mass of NaCl = 58 g/mol

Now we will put the values in formula.

0.14 mol = Mass of NaCl / 58 g/mol

Mass of NaCl = 0.14 mol  ×  58 g/mol

Mass of NaCl = 8.12 g of NaCl

Thus, 0.14 moles of NaCl contain 8.12 g of NaCl.

4 0
3 years ago
3. A compound consists of 91.63 grams of carbon, 7.69 grams of hydrogen and 40.81 grams of
Vikentia [17]

Answer:

Molecular formula = C₁₂H₁₂O₄

Empirical formula is C₃H₃O.

Explanation:

Given data:

Mass of C = 91.63 g

Mass of H = 7.69 g

Mass pf O = 40.81 g

Molar mass of compound = 220 g/mol

Empirical formula = ?

Molecular formula = ?

Solution:

Number of gram atoms of H = 7.69 / 1.01 = 7.61

Number of gram atoms of O = 40.81 / 16 = 2.55

Number of gram atoms of C = 91.63 / 12 = 7.64

Atomic ratio:

            C                      :      H                :         O

           7.64/2.55          :    7.61 /2.55    :       2.55/2.55

               3                     :          3               :        1

C : H : O = 3 : 3 : 1

Empirical formula is C₃H₃O.

Molecular formula:

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

Empirical formula mass  = 3×12+ 3×1.01 +16 = 55.03

n = 220 / 55.03

n = 4

Molecular formula = 4 (empirical formula)

Molecular formula = 4 (C₃H₃O)

Molecular formula = C₁₂H₁₂O₄

8 0
3 years ago
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