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Andreyy89
3 years ago
10

How many grams of Na2CO3 are present in 11.8 mL of a solution that is 22.0% Na2CO3 by mass? The density of the solution is 1.10

g/mL.

Chemistry
1 answer:
Sergeeva-Olga [200]3 years ago
5 0

Answer:

The Answer is 2,86 grs Na2CO3

Explanation:

What we have to do is find the mass of Na2CO3 as a pure component or solute. That's because the 11,8 mL are a solution of Na2CO3. This means, the sum between the solute Na2CO3 and water. To find the grams of Na2CO3 as pure component we create a factor series as is shown in the attached file.

Data:

Density of solution (ρ) = 1,10 grs sln Na2CO3/mL sln Na2CO3

Mass Percentage (%) = 22 grs Na2CO3/100 grs sln Na2CO3  

The procedure is explained in the attached file

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When two atoms forming a bond differ in their electronegativities at that time bond polarity is generated

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D

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Read more about Acidic and basic compounds here brainly.com/question/4046668

4 0
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