Answer:
The Answer is 2,86 grs Na2CO3
Explanation:
What we have to do is find the mass of Na2CO3 as a pure component or solute. That's because the 11,8 mL are a solution of Na2CO3. This means, the sum between the solute Na2CO3 and water. To find the grams of Na2CO3 as pure component we create a factor series as is shown in the attached file.
Data:
Density of solution (ρ) = 1,10 grs sln Na2CO3/mL sln Na2CO3
Mass Percentage (%) = 22 grs Na2CO3/100 grs sln Na2CO3
The procedure is explained in the attached file
Answer :
The steps involved in the electron dot structure of are :
First we have to determine the total number of valence electron in .
Number of valence electrons in N = 5
The charge on N is (-3). So, we add 3 electrons.
Total number of valence electrons = 5 + 3 = 8 electrons
The image is shown below.
