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hammer [34]
2 years ago
5

Use the solubility rules from the Lab 4 introduction and your knowledge of qualitative separation schemes from the lab to answer

the following questions.
The qualitative analysis experiment you did is actually an abbreviated version of a much larger analysis scheme in which many different cations are separated and identified. Suppose a mixture contains Ag+, K+, NH4+, Hg22+, Pb2+, Mg2+, Sr2+, Ba2+, Cu2+, Al3+ and Fe3+.
(a) Which of the following ions could you separate, by causing them to precipitate, with the addition of HCl? (Hint: HCl is a source of chloride ions. Select all that apply.)
Ag+ K+ NH4+
Hg22+ Pb2+ Mg2+
Sr2+ Ba2+ Cu2+
Al3+ Fe3+
(b) After the addition of HCl, the above sample is centrifuged and decanted. Which of the following cations remaining in the supernatant could you separate, by causing them to precipitate, with the addition of H2SO4? (Hint: H2SO4 is a source of sulfate ions. Select all that apply.)
Ag+ K+ NH4+
Hg22+ Pb2+ Mg2+
Sr2+ Ba2+ Cu2+
Al3+ Fe3+
(c) After the addition of H2SO4, the above sample is centrifuged and decanted. Which of the following cations remaining in the supernatant could you separate, by causing them to precipitate, with the addition of H2CO3? (Hint: H2CO3 is a source of HCO3− and carbonate ions. Select all that apply.)
Ag+ K+ NH4+
Hg22+ Pb2+ Mg2+
Sr2+ Ba2+ Cu2+
Al3+ Fe3+
(d) Choose one of the cations above and write the net precipitation reaction that occurs. (Use the lowest possible coefficients. Include states-of-matter under the given conditions in your answer.)
Cu2+(aq) + (CO3)2-(aq) → CuCO3(s)
Your answer contains an improperly or incompletely formatted chemical formula. Your answer contains improper superscript or subscript
Chemistry
1 answer:
frez [133]2 years ago
8 0

Answer:

Explanation:

a ) silver chloride AgCl and lead chloride PbCl₂  Hg₂Cl₂ ,  are not dissolved in ware

so Ag⁺ and Pb⁺² Hg₂ ⁺² will precipitate out .

b ) BaSO₄ , SrSO₄  are insoluble

Ba⁺² and Sr⁺² will precipitate out .

c )

Al₂( CO₃)₃ ,  Fe₂(CO₃)₃  , CuCO₃ insoluble .

Al⁺³ and Fe⁺³ and Cu⁺² will be insoluble .

d )  

2Fe⁺³(aq) + 3CO₃⁻²(aq) = Fe₂(CO₃)₃ (s)

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What total volume of ozone measured at a pressure of 24.5 mmHg and a temperature of 232 K can be destroyed when all of the chlor
ddd [48]

Answer:

1.75272\ \text{m}^3

Explanation:

The breakdown reaction of ozone is as follows

CF_3Cl + UV \rightarrow CF_3 + Cl

Cl + O_3 \rightarrow ClO + O_2

O_3 + UV \rightarrow O_2 + O

ClO + O \rightarrow Cl + O_2

It can be seen that 2 moles of ozone is required in the complete cycle

So for 10 cycles, 20 moles of ozone is required

m = Mass of CF_3Cl = 15.5 g

M = Molar mass of CF_3Cl = 104.46 g/mol

P = Pressure = 24.5 mmHg

T = Temperature = 232 K

R = Gas constant = 62.363\ \text{L mmHg/K mol}

Number of moles is given by

n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{15.5}{104.46}\\\Rightarrow n=0.1484\ \text{moles}

20\ \text{moles} = 20\times 0.1484 = 2.968\ \text{moles}

From ideal gas law we have

PV=nRT\\\Rightarrow V=\dfrac{nRT}{P}\\\Rightarrow V=\dfrac{2.968\times 62.363\times 232}{24.5}\\\Rightarrow V=1752.72\ \text{L}=1.75272\ \text{m}^3

For 20 cycles of the reaction the volume of the ozone is 1.75272\ \text{m}^3.

7 0
3 years ago
Which type of reaction?
polet [3.4K]
condensation polymerization, since a byproduct of the reaction is a single molecule of water (hence condensation of water)

addition polymerization is if you add the two polymers together like blocks and should have no byproducts

esterification is when you combine an organic acid with an alcohol. Since neither of the two polymers look like acids, you can rule this out.

never heard of saponification, Im an mechanical engineer not an organic chemist

3 0
3 years ago
_____ were common ocean scavengers long ago, and they are frequently found in fossilized form.
quester [9]

Answer:

a. trilobites.

Explanation:

6 0
3 years ago
If 45.8 grams of potassium chlorate decomposes, how many grams of oxygen gas can be produced? 2KClO3 → 2KCl + 3O2
natta225 [31]
To do this problem, we must first look at the balanced chemical equation for the decomposition of potassium chlorate: 

<span>2KClO3 --> 2KCl + 3O2 </span>

<span>We can take the given amount of grams, and use the molar mass of KClO3 to convert to moles. Then, we can use the stoichiometric ratios to relate moles of KClO3 to moles of O2. </span>

<span>(39.09)+(35.45)+(3*15.99)= 122.51 g/ mol = molar mass of KClO3 </span>
<span>45.8 g KClO3/ 122.51 g/ mol KClO3 = .374 moles KClO3 </span>
<span>.374 mol KClO3 *(3 moles O2/2 mol KClO3)= .560 moles O2 </span>

<span>Once we have moles of O2, we can convert to grams of O2. </span>

<span>(2*15.99)= 31.98 g/mol = molar mass of O2 </span>
<span>(.560 moles O2) (31.98 g/mol)= 17.91 g O2 </span>


<span>Hope this helps :)</span>
3 0
3 years ago
Convert 5.8 km to the unit mm. <br> 0.0000058 mm <br> 0.0058 mm <br> 5,800 mm <br> 5,800,000 mm
spin [16.1K]
Its going to b 5,800,000 due to each Km being 1,000,000 Mm
Hope this helps :D
5 0
2 years ago
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