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hammer [34]
3 years ago
5

Use the solubility rules from the Lab 4 introduction and your knowledge of qualitative separation schemes from the lab to answer

the following questions.
The qualitative analysis experiment you did is actually an abbreviated version of a much larger analysis scheme in which many different cations are separated and identified. Suppose a mixture contains Ag+, K+, NH4+, Hg22+, Pb2+, Mg2+, Sr2+, Ba2+, Cu2+, Al3+ and Fe3+.
(a) Which of the following ions could you separate, by causing them to precipitate, with the addition of HCl? (Hint: HCl is a source of chloride ions. Select all that apply.)
Ag+ K+ NH4+
Hg22+ Pb2+ Mg2+
Sr2+ Ba2+ Cu2+
Al3+ Fe3+
(b) After the addition of HCl, the above sample is centrifuged and decanted. Which of the following cations remaining in the supernatant could you separate, by causing them to precipitate, with the addition of H2SO4? (Hint: H2SO4 is a source of sulfate ions. Select all that apply.)
Ag+ K+ NH4+
Hg22+ Pb2+ Mg2+
Sr2+ Ba2+ Cu2+
Al3+ Fe3+
(c) After the addition of H2SO4, the above sample is centrifuged and decanted. Which of the following cations remaining in the supernatant could you separate, by causing them to precipitate, with the addition of H2CO3? (Hint: H2CO3 is a source of HCO3− and carbonate ions. Select all that apply.)
Ag+ K+ NH4+
Hg22+ Pb2+ Mg2+
Sr2+ Ba2+ Cu2+
Al3+ Fe3+
(d) Choose one of the cations above and write the net precipitation reaction that occurs. (Use the lowest possible coefficients. Include states-of-matter under the given conditions in your answer.)
Cu2+(aq) + (CO3)2-(aq) → CuCO3(s)
Your answer contains an improperly or incompletely formatted chemical formula. Your answer contains improper superscript or subscript
Chemistry
1 answer:
frez [133]3 years ago
8 0

Answer:

Explanation:

a ) silver chloride AgCl and lead chloride PbCl₂  Hg₂Cl₂ ,  are not dissolved in ware

so Ag⁺ and Pb⁺² Hg₂ ⁺² will precipitate out .

b ) BaSO₄ , SrSO₄  are insoluble

Ba⁺² and Sr⁺² will precipitate out .

c )

Al₂( CO₃)₃ ,  Fe₂(CO₃)₃  , CuCO₃ insoluble .

Al⁺³ and Fe⁺³ and Cu⁺² will be insoluble .

d )  

2Fe⁺³(aq) + 3CO₃⁻²(aq) = Fe₂(CO₃)₃ (s)

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For the reaction 2Na + Cl2 → 2NaCl, how many grams of chlorine gas are required to react completely with 57.5 mol of sodium?
Step2247 [10]

Answer:

1019.27 g.

Explanation:

  • For the balanced reaction:

<em>2Na + Cl₂ → 2NaCl,</em>

It is clear 2 moles of Na with 1 mole of Cl₂ to produce 2 moles NaCl.

  • Firstly, we need to calculate the no. of moles of Cl₂ is needed to react with 57.5 mol Na:

2 moles of Na need → 1 mol of Cl₂, from the stichiometry.

57.5 moles of Na need → ??? mol of Cl₂.

<em>∴ The no. of moles of Cl₂ is needed to react with 57.5 mol Na =</em> (1 mol)(57.5 mol)/((2 mol) <em>= 28.75 mol.</em>

<em>∴ the mass of Cl₂ is needed to react with 57.5 mol Na = (no. of moles of Cl₂)(molar mass of Cl₂) =</em> (28.75 mol)(35.453 g/mol) <em>= 1019.27 g.</em>

4 0
3 years ago
Write the configuration for electron: 4, 2, -1, +12
Alexxandr [17]

Answer:

-1

Explanation:

electrons are negative

4 0
2 years ago
Mercury (II) oxide decomposes to mercury and oxygen. In the chemical equation below, what is the subscript, x, on the oxygen equ
sertanlavr [38]
The correct subscript for the reaction would be two. Oxygen gas exists as a diatomic molecule in nature. Also, the subscript two would balance the reaction. In balancing reactions, it is important that the atoms on each side of the reaction is equal.
7 0
3 years ago
An unknown sample of mystery element T is analyzed. According to the data 7.42% of the element is ^6T and 92.58% is ^7T. The tru
Pepsi [2]

Answer:

\boxed{\text{6.95 u; Li}}

Explanation:

1. Atomic mass of T

To get the atomic mass of T, you calculate the weighted average of the atomic masses of the isotopes.

That is, you multiply the atomic mass of each isotope by a number representing its relative importance (e.g.., its percent of the total).

\begin{array}{ccrcr}\textbf{Atom} & \textbf{Mass/u} &\textbf{Percent} & \textbf{Calculation}& \textbf{Result/u}\\^{6}\text{T}& 6.02 & 7.42 & 6.02 \times 0.0742 & 0.45\\^{7}\text{T}& 7.02 & 92.58 & 7.02 \times 0.9258& 6.50\\& & &\text{TOTAL } = &\textbf{6.95}\\\end{array}

2. Identity of T

Lithium has an atomic mass of 6.64 u.

Element T is lithium.

 

8 0
3 years ago
The average kinetic of a gas remains the same when A. It’s volume is decreased B. It’s tell us decreasedC. It’s tell is increase
skad [1K]

Answer

A. Its volume is decreased

Explanation

If we compress a gas (decrease) without changing its temperature, the average kinetic energy of the gas particles remains the same.

At a constant temperature, the kinetic energy of particles remains the same. If the volume is reduced at a constant temperature, then the number of particles in unit volume or area increases. If there is an increased number of particles in the unit area then it increases the frequency of collisions per unit area.

At constant temperature, the smaller the volume of the container, the larger the pressure.

6 0
1 year ago
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