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Brut [27]
3 years ago
9

What is 66 2/3% of 39 ? please explain thoroughly please and thank you!

Mathematics
2 answers:
Rom4ik [11]3 years ago
7 0
66 2/3% is the same thing as saying 2/3, therefore 2/3 of 39, given that 39 is divisible by 3, would be 26.  Have a nice day! :)
miskamm [114]3 years ago
5 0
<span> 66 2/3 x 39 = 39/3 x 2 = 13 x 2 = 26
this is quite difficult but i got 26

</span>
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6 0
3 years ago
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Determine the domain and range for each of the following:
LiRa [457]

Answer

Domain is the values x can be.

Range is the values y can be.

1st Graph)

D: -8 < x < 3

R:  3 < y < 9

2nd Graph)

D: -4<x<4

R: -4<y<4

3rd Graph)

-Note that this graph has an open and closed circle. Which means one is open and the other is closed on the interval. I will use brackets to make it easier.

D: [-4,3)

R: (-6,2)

6 0
3 years ago
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Sedbober [7]
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6 0
4 years ago
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Find an equation with vertical asymptotes 1 and 4 and horizontal asymptote 1 please help
Brilliant_brown [7]

Answer:

y = 1 + 1/((x -1)(x -4))

Step-by-step explanation:

To get vertical asymptotes at 1 and 4, you need factors (x -1) and (x -4) in the denominator. As x approaches 1 or 4, one of these will approach zero, and the function value will approach infinity.

To get a horizontal asymptote of 1, the function must approach the value 1 when the value of x gets large (positive or negative). This can generally be accomplished by simply adding 1 to a fraction that approaches zero when x is large.

Here, we make the fraction be the one that gives the vertical asymptotes, and we simply add 1 to it.

... y = 1 + 1/((x -1)(x -4))

If you like, this can be "simplified" to ...

... y = (x² -5x +5)/(x² -5x +4)

_____

In this rational expression form, please note that the numerator and denominator have the same degree. That will be the case when there is a horizontal asymptote. (When a slant asymptote, the numerator degree is 1 higher than the denominator.) The ratio of the coefficients of the highest degree terms is the horizontal asymptote value (or the slope of a slant asymptote).

6 0
3 years ago
Suppose that y varies inversely with x.write an equation for the inverse variation. Y=6 when x=8
sasho [114]

Answer: y = 48/x

Step-by-step explanation:

y ∝ 1/x

Introducing the proportionality constant, we have

y = k/x

substituting the value of x and y , we have

6 = k/8

k = 48

Therefore the equation becomes

y = 48/x

8 0
3 years ago
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