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3 years ago

10

The HA theorem is a special case of what postulate

2 answers:

eduard3 years ago

7 0

Answer:

AAS theorem

Step-by-step explanation:

apex

Nadya [2.5K]3 years ago

5 0

The HA Theorem is a special case of proving that two triangles are congruent.

It states that if both hypotenuses and a pair of acute angles of two right triangles are congruent, then the triangles are congruent.

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Tessa is taking her family out to dinner and the bill is $250. She has a coupon for 15% off. After the discount is applied, she

IgorLugansk [536]

Answer:

$255

Step-by-step explanation:

250*.85=212.5

212.5*1.2=255

8 0

3 years ago

Cedric and Insha solved the same equation using the calculations below.

Mariulka [41]

The first working out is correct, z = 3

3 0

3 years ago

If you have a vertical angle and the side angles are 83 and 83 whats the other one?

Hoochie [10]

Answer:

97°

Step-by-step explanation:

you do $83*2=166$ and then $360-166=194$ which is the total sum of the two unknown vertical angles. once you have that, divide it by 2 to get $194/2=97°$ as the measure of each individual unknow vertical angle

7 0

3 years ago

Read 2 more answers

Add these two expressions. (–45t + 53s) and (–3 – 75s + 2t) 65t + 415s – 3 –145t – 115s – 3 –115t + 113s – 3 115t – 415s + 2

serious [3.7K]

Answer:

- 43t - 22s - 3

Step-by-step explanation:

(–45t + 53s) + (–3 – 75s + 2t)

Opening the brackets

-45t + 53s -3 - 75s + 2t

Collecting like terms

-45t + 2t + 53s - 75s -3

Simplify the expression

-43t -22s - 3

4 0

2 years ago

Ab^2-4/10 when a=4 b=6

hammer [34]

$\huge\text{Hey there!}$

$\large\boxed{\rm{\dfrac{ab^2 - 4}{10}}}$

$\large\boxed{\rm{\rightarrow\dfrac{\bold{4(6)}^2 -4}{10}}}$

$\large\boxed{\rm{6^2}}$

$\large\boxed{\rm{= 6 \times6}}$

$\large\boxed{\rm{= \bf 36}}$

$\large\boxed{\rm{\rightarrow\dfrac{4(\bold{36)}- 4}{10}}}}$

$\large\boxed{\rm{4(36)}}$

$\large\boxed{\rm{= \bf 144}}}$

$\large\boxed{\rm{\rightarrow\dfrac{\bold{144} - 4}{10}}}$

$\large\boxed{\rm{\bold{144} - 4}}$

$\large\boxed{= \rm{\bf 140}}}$

$\large\boxed{\rm{\rightarrow\dfrac{\bold{140}}{10}}}$

$\large\boxed{\rm{= \bf 14}}$

$\huge\boxed{\rm{Therefore, your\ answer\ is: \mathsf{14}}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

4 0

2 years ago