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vovangra [49]
3 years ago
8

Write an exponential function to represent both of these

Mathematics
1 answer:
Hunter-Best [27]3 years ago
3 0

Answer:

1. y = 2(3)^x \ or \ y = 6^x

2. y = 10(2)^x \ or \ y = 20^x

Step-by-step explanation:

1. Solution for 1st part.

Given:

Ben shared his post with 2 friends

Each of those friends shares with 3 more every day.

the number of shares triples every day.

From the data given above, we can make the following:

N(0) = 2 \times 3^0 = 2\\N(1) = 2 \times 3^1 = 6\\N(2) = 2 \times 3^2 = 18

An exponential function is represented by:

y = ab^x

where a is the initial value and b is the growth rate.

The exponential function for this case would be:

y = 2(3)^x \ or \ y = 6^x

2. Solution for part 2.

Given:

Carter shared his post with 10 friends.

each share with only 2 people each day.

From the data given above, we can make the following:

N(0) = 10 \times 2^0 = 10\\N(1) = 10 \times 2^1 = 20

An exponential function is represented by:

y = ab^x

where a is the initial value and b is the growth rate.

The exponential function for this case would be:

y = 10(2)^x \ or \ y = 20^x

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Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

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Relating the margin of error with the sample size:

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\alpha = \frac{1 - 0.9}{2} = 0.05

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For this problem, we have that \sigma = 14300, M = 5863. So

M = z\frac{\sigma}{\sqrt{n}}

5863 = 1.645\frac{14300}{\sqrt{n}}

5863\sqrt{n} = 1.645*14300

\sqrt{n} = \frac{1.645*14300}{5863}

(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2

n = 16

The sample size was of 16.

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