<h2><em><u>V</u></em><em><u>A</u></em><em><u>L</u></em><em><u>U</u></em><em><u>E</u></em><em><u> </u></em><em><u> </u></em><em><u>O</u></em><em><u>F</u></em><em><u> </u></em><em><u>X</u></em><em><u>=</u></em><em><u>5</u></em><em><u>0</u></em><em><u> </u></em><em><u>D</u></em><em><u>E</u></em><em><u>G</u></em><em><u>R</u></em><em><u>E</u></em><em><u>E</u></em><em><u> </u></em><em><u>A</u></em><em><u>N</u></em><em><u>D</u></em><em><u> </u></em><em><u>V</u></em><em><u>A</u></em><em><u>L</u></em><em><u>U</u></em><em><u>E</u></em><em><u> </u></em><em><u>O</u></em><em><u>F</u></em><em><u> </u></em><em><u>Y</u></em><em><u>=</u></em><em><u>1</u></em><em><u>0</u></em><em><u>0</u></em><em><u> </u></em><em><u>D</u></em><em><u>E</u></em><em><u>G</u></em><em><u>R</u></em><em><u>E</u></em><em><u>E</u></em></h2>
Answer:
95degrees
Step-by-step explanation:
Answer:
I think its 6.40 but I'm not sure.
Answer:
The correct option is C. either a t test or an analysis of variance can be performed.
Step-by-step explanation:
Consider the provided information.
- The t-test, is used for whether the means of two groups are equal or not. The assumption for the test is that both groups are sampled from normal distributions with equal variances.
- Analysis of Variance (ANOVA) is a statistical method evaluating variations between two or more methods. ANOVA is used in a study to analyze the gaps between group methods.
- ANOVA is used not for specific differences between means, but for general testing.
- The chi-squared test is often used to evaluate whether there was a significant difference in one or more groups between the predicted frequencies and the observed frequencies.
Hence, Either a t test or an analysis of variance can be performed to determine whether the means of two population are equal.
Therefore, the correct option is C. either a t test or an analysis of variance can be performed.
