For a comparison of the nucleus 5626fe, the density of the nucleus 112 48cd is mathematically given as the same.
n(Cd) / n(Fe)=1
<h3>What is the density of the nucleus 112 48cd?</h3>
Generally, the equation for the density is mathematically given as
d=\frac{A}{4/3}\piR^3
Therefore
n(Cd) / n(Fe) = [A (Cd) / (A Fe) ] * [ R (Fe) / R (Cd)]^3
n(Cd) / n(Fe)= (112 / 56 ) * (1/1.26)3
n(Cd) / n(Fe)=1
In conclusion, The ratio of n(Cd) = n(Fe) is 1, hence same
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brainly.com/question/14010194
Answer:
According to avogadro's law, 1 mole of every substance contains avogadro's number 
of particles and weighs equal to its molecular mass.
To calculate the moles, we use the equation:
a. moles in 14.08 g of 
= 
molecules in 14.08 g of = 
b. moles in 17.75 g of NaCl = 
molecules in 17.75 g of 
= 
formula units 17.75 g of =
c. moles in 20.06 g of 
= 
formula units in 20.06 g of = 
Answer:
hope this help !
Explanation:
Use the given functions to set up and simplify 173 ° C .
1.5 =
CH4 = CH4
4.4 = CH4
173 ° C = CH4
<span>The answer is hypertonic. In osmosis, water
molecules move from a hypotonic solution to the hypertonic solution, through a
semipermeable membrane. This occurs until
both solutions become isotonic relative to each other. In osmosis, only
the movement of water molecules occurs since the ions are large enough to pass
through the pores of the semipermeable membrane,
in this case, the cell membrane. Due to
loss of water in the process of osmosis, the cells in the fingers of the swimmers
shrunk hence looked shriveled.</span>
