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Tatiana [17]
3 years ago
8

All common cations are smaller than all common anions except one of thesea. Rubidiumb. Calciumc. Magnesiumd. sodium

Chemistry
1 answer:
olga_2 [115]3 years ago
6 0
The answer is <span>a. Rubidium

A cation is an ion that has a positive charge. The charge positive because it loses electrons. The radius of an atom is influenced by the electron because it is found at the outer layer of the atom. Since cation has less electron and anion get more electron, the radius of cation will be smaller than anion. 
Rubidium is the biggest cation because it is located in the lowest row, thus having most electron count.</span>
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Elina [12.6K]

1. Molarity : 0.25 M

2. mol CH₄ = 7.4 moles

mol O₂ = 14.8 moles

<h3>Further explanation</h3>

1.

Given

83.2 g CuCl2 in 2.5 liters of water

Required

the molarity

Solution

Molarity : mol solute per liter of solution(not per liter of solvent)

  • mol solute

mol solute = mol CuCl₂

mol CuCl₂ = mass : MW CuCl₂

mol CuCl₂ = 83.2 : 134.45

mol CuCl₂ = 0.619

  • Molarity

Molarity(M) = mol : V

Assume density CuCl₂ = 3.39 g/cm³

volume CuCl₂ = 8.32 g : 3.39 g/cm³ = 2.45 cm³=2.45 x 10⁻³ L

With this small volume value of CuCl₂, the volume of the solute is sometimes neglected in calculating molarity

volume of solution = 2.5 L + 2.45 x 10⁻³ L = 2.50245 L

Molarity(M) = mol : V

M = 0.619 : 2.50245 L = 0.247≈0.25

2.

Given

Reaction

The correct balanced reaction:

CH4 + 2O2 → CO2 + 2H2O

7.4 moles CO2

Required

moles of methane (CH4) and oxygen gas (O2)

Solution

From the equation, mol ratio of CO₂ : CH₄ : O₂ = 1 : 1 : 2

mol CH₄ = mol CO₂ = 7.4 moles

mol O₂ = 2 x mol CO₂ = 2 x 7.4 moles = 14.8 moles

3 0
3 years ago
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