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In-s [12.5K]
3 years ago
13

A greater force is required to move an object with a larger mass than one with a smaller mass.

Chemistry
2 answers:
marishachu [46]3 years ago
7 0

Answer:

Explanation:

what do u need to know

charle [14.2K]3 years ago
5 0
The greater the force that is applied to an object of a given mass, the more the object will accelerate. The greater the mass of an object, the less it will accelerate when a given force is applied. For example, doubling the mass of an object results in only half as much acceleration for the same amount of force. Hope this helps!
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Trace amounts of sulfur (S) in coal are burned in the presence of diatomic oxygen (O2) to form sulfur dioxide (SO2). Determine t
Mashcka [7]

Answer:

0.99 kg O₂

1.9 kg SO₂

Explanation:

Let's consider the reaction between sulfur and oxygen to form sulfur dioxide.

S + O₂ → SO₂

The mass ratio of S to O₂ is 32.07:32.00. The mass of oxygen required to react with 1 kg of sulfur is:

1 kg S × (32.00 kg O₂/32.07 kg S) = 0.998 kg O₂

The mass ratio of S to SO₂ is 32.07:64.07. The mass of sulfur dioxide formed when 1 kg of sulfur is burned is:

1 kg S × (64.07 kg SO₂/32.07 kg S) = 1.99 kg SO₂

3 0
4 years ago
The value of the equilibrium constant for a reaction is 2.65 x 10-6 at 35° Calculate the value of LaTeX: \DeltaΔG°rxn.
stealth61 [152]

Answer:

The answer is "33.95 \bold{ \frac{kj}{mol}}\\".

Explanation:

Formula:

\bigtriangleup G_0= -R \times T l_n \times K_{eq}\\

where

K_{eq}  = \text{equilibrium constant}\\

Given value:

T =35^{\circ} C\\

convert temperature celsius (°C) to Kelvin (K):

= (273+45) \ kelvin \\\\= 318 \ Kelvin \\\\= 318 \ K

R = 8.314 \ \ \frac{J}{ mol \cdot K}

\bigtriangleup G_0= -(8.314 ) \times 31.8 \times  l_n (2.65\times 10^{-6})\\

        =-(8.314 ) \times 31.8T l_n \times (2.65\times 10^{-6})\\\\

After solving the value it will give:

        = 33.95  \bold{ \frac{kj}{mol}}\\

3 0
3 years ago
3. Concentric circles (one smaller circle inside another). As
Agata [3.3K]

Answer:

Bohr's "planetary project" was widely accepted because he was able to explain a factor that Ruthford failed to achieve. Bohr was able to explain how electrons and energy worked in a simple atom, such as hydrogen, which consists of an electron orbiting a single proton.

In addition, he was able to explain, using the principles of gravity, how electrons do not fall on top of the proton but rather orbit around the proton.

Explanation:

Danish physicist Niels Bohr proposed an atomic model for the hydrogen atom which was later extended to other elements. Its model is based on the Solar System, in which the planets rotate around the sun. For Bohr, electrons rotate in orbit around the atomic nucleus grouped into energy levels.

Until 1913, there was no satisfactory model that explained even the simplest of atoms - hydrogen, which consists of an electron orbiting a single proton.

By assigning the concept of energy levels, Bohr was able to create a version of the hydrogen atom that was possibly stable and satisfying spectral observations. Until then, all theoretical predictions suggested that it should not exist for more than a split second - a failure that bothered physicists a great deal. It was therefore a monumental advance.

Bohr was also able to explain why electrons do not fall on protons using concepts of gravity. In Bohr's atomic model, electrons rotate around the nucleus like planets around the sun. According to Bohr, an electron does not fall into the nucleus because it cannot: its orbits are like steps in a ladder. We may be in one or the other but not in two. Imagine the atom as a kind of tiny football stadium.

The core is in the center of the lawn. Electrons can run around the steps of the stands. From time to time, they jump from step to step. If they go up they use energy, down they release energy.

However, electrons can never leave the stands to invade the field. Bohr did not explain why the ban.

8 0
4 years ago
Which of these objects converts light to chemical energy? four objects
Papessa [141]
It would be a ehtanol plant
3 0
3 years ago
Read 2 more answers
The reaction A+B-> C+D rate=k[A][B]^2 has an initial rate of 0.0810 M/s. What will the initial rate be if [A] is halved and [
makkiz [27]
The first to do is to isolate the constant, k, to one side. The rate expression would then be:

k = rate/ <span>[A][B]^2 

This constant, k, will be the same for the given reaction at a certain temperature. Then, we can relate a second rate to this reaction.

</span>rate1/ [A1][B1]^2 = rate2/ [A2][B2]^2 

First question:
0.0810 / [A1][B1]^2 = rate2/ <span>[A2/2][3B2]^2 
rate2 = (</span>0.0810 [A2/2][3B2]^2 )/ [A1][B1]^2
rate2 = 0.3645 M/s

Second Equation:
0.0810 / [A1][B1]^2 = rate2/ <span>[A2/2][3B2]^2 
rate2 = (</span>0.0810 [3A2][B2/2]^2 )/ [A1][B1]^2
<span>rate2 = 0.0608 M/s</span>
3 0
3 years ago
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