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Inessa [10]
3 years ago
14

Predict the major and minor products of the following reaction. Name the products using systematic names.CH3CH2CH = CH2+H2O H+--

---> major product + minor product
Chemistry
1 answer:
BartSMP [9]3 years ago
6 0
<h3><u>Answer;</u></h3>

Major product; 2-Butanol ;(CH3CH2CH(OH)-CH3)

Minor product; none

<h3><u>Explanation;</u></h3>
  • Alkenes undergo an addition reaction with water in the presence of a catalyst to form an alcohol. This type of addition reaction is called hydration.
  • For example; in hydration of 2-butene, Water adds across the double bond in a Markovnikov fashion to form 2-butanol

CH3CH2CH=CH2 + H2O (acid catalyst) -----> CH3CH2CH(OH)-CH3

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How many electrons would be found in the Ion who’s symbol is I-
Vesnalui [34]

Answer:

54

Explanation:

Given symbol of the element:

                   I⁻

Number of electrons found in an ion with the symbol:

  This is a iodine ion:

         For an atom of iodine:

                   Electrons  = 53

                   Protons  = 53

                   Neutrons  = 74

An ion of iodine is one that has lost or gained electrons.

For this one, we have a negatively charged ion which implies that the number of electrons is 1 more than that of the protons.

  So, number of electrons  = 53 + 1  = 54

The number of electrons in this ion is 54

6 0
2 years ago
Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =
MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{c}

For a general chemical reaction:

aA+bB\rightleftharpoons cC+dD

The expression for K_{eq} is written as:

K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)

The expression of K_c for above equation is:

K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}

We are given:

[H_2S]_{eq}=0.671M

[O_2]_{eq}=0.587M

K_c=1.35

Putting values in above expression, we get:

1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}

[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M

Hence, the equilibrium concentration of water is 0.597 M

8 0
3 years ago
Which landform is located at the mouth of the river?
nevsk [136]
Landforms. At the mouth of a river, the change in flow condition can cause the river to drop any sediment it is carrying. This sediment deposition can generate a variety of landforms, such as deltas, sand bars, spits, and tie channels.

3 0
3 years ago
What is gravity?????????
SashulF [63]
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5 0
3 years ago
Read 2 more answers
A sample of gas contains 0.1100 mol of HBr(g) and 5.00x10^-2 mol of Cl2(g) and occupies a volume of 5.85 L. The following reacti
Vesna [10]

The volume of the sample after the reaction : V₂=5.484 L

<h3>Further explanation</h3>

Given

Reaction

2HBr(g) + Cl2(g) => 2HCl (g)+Br2(g)

0.1100 mol of HBr(g)

5x10⁻² mol of Cl2(g)

Required

The volume of the sample after reaction

Solution

Find limiting reactant :

0.11/2 : 0.05/1 = 0.055 : 0.05

Limiting reactant : Cl₂

mol Products based on mol Cl₂

mol products = mol HCl + mol Br₂

mol products = 2/1x0.05 + 1/1x0.05

mol products = 3 x 0.05 = 0.15

mol reactants = 0.11 + 0.05 = 0.16

<em>From Avogadro's law, </em>

In the same T, P, and V, the gas contains the same number of molecules  

So the ratio of gas volume will be equal to the ratio of gas moles  

 V₁/n₁=V₂/n₂

1 = reactants, 2 = products

Input the value :

5.85/0.16=V₂/0.15

V₂=5.484 L

6 0
3 years ago
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