All categories

3 years ago

What is the y-intercept?

Mathematics

2 answers:

MrRissso [65]3 years ago

6 0

The y intercept is zero because it crosses the y axis at 0

kvasek [131]3 years ago

4 0

Answer:

The y-intercept is 0

Step-by-step explanation:

You might be interested in

Explain how an estimate help you to place the decimal point when multiplying 3.9x5.3?

trapecia [35]

You can estimate 3.9 times 5.3 to 4 times 5 which is 20
so if the answer is around 20, you know that you will have exactly 2 digits before the decimal place

6 0

3 years ago

$855 in an account for one year at a 6% interest rate . can you help me ?

trapecia [35]

So for this, you will be using the exponential equation formula, which is y=ab^x , with a = initial value and b = growth/decay.

Since we start out with 855, that is your a variable.

And since this is a growth by 6%, add 1 and 0.06 (6% in decimal form) together, which is 1.06. That is your b variable.

In this case, time is the independent variable. therefore 1 year is the x variable.

Using the prior info, we can form our equation to be: y = 855(1.06)^1 . From here we can solve for y.

Firstly, solve 1.06^1: y = 855(1.06)

Next, multiply everything, and your answer should be y = 906.30 . In this context, there will be $906.30 in your account after 1 year.

8 0

3 years ago

QRST is a parallelogram. Determine the measure of ∠Q<br> PLS HELP

Morgarella [4.7K]

4x+10=5x-3
Subtract 4x from both sides
10= 5x-4x-3
Add 3 to both sides
13=x

4(13)+10
52+10

Q=62

7 0

3 years ago

Read 2 more answers

If p(x) = 2 (x2 + 1) – 5, what is the value of p (3)?

Dima020 [189]

The value of p(3) is is 3

8 0

3 years ago

The velocity of an object is given by the following function defined on a specified interval. Approximate the displacement of th

harkovskaia [24]

Answer:

The displacement of the object on this intervals is 1.33 m.

Step-by-step explanation:

Given that,

The function of velocity is

$v=\dfrac{1}{2t+4}\ m/s$

For 0 ≤ t ≤8 , n = 2

We need to calculate the intervals

Using formula for intervals

For, n = 1

$\Delta x=\dfrac{t_{f}-t_{i}}{n}$

$\Delta x=\dfrac{8-0}{2}$

$\Delta x=4$

So, The intervals are (0,4), (4,8)

We need to calculate the velocity

Using given function

$v=\dfrac{1}{2t+4}$

For first interval (0,4),

Put the value into the formula

$v_{0}=\dfrac{1}{2\times0+4}$

$v_{0}=\dfrac{1}{4}$

For first interval (4,8),

Put the value into the formula

$v_{4}=\dfrac{1}{2\times4+4}$

$v_{4}=\dfrac{1}{12}$

We need to calculate the total displacement

Using formula of displacement

$D=(v_{0}+v_{4})\times(\Delta x)$

Put the value into the formula

$D=(\dfrac{1}{4}+\dfrac{1}{12})\times4$

$D=1.33\ m$

Hence, The displacement of the object on this intervals is 1.33 m.

5 0

4 years ago