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soldi70 [24.7K]
3 years ago
8

The sum of two numbers is 3 and the product is -40. Find the numbers . List each number separates by a comma

Mathematics
1 answer:
pshichka [43]3 years ago
5 0

it is 8, and -5 that is the answer

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How to solve this one​
Stells [14]

Answer:

(-5,1)

Step-by-step explanation:

Add it together

3x - 2x = x

y - y = 0

9 - 14 = -5

x = -5

Choose a random equation, doesn't matter.

3x + y = -14

3(-5) + y = -14

-15 + y = -14

y = -14 + 15

y = 1

7 0
2 years ago
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777dan777 [17]

Answer:

A: positive B: Negative C: Positive

Step-by-step explanation:

4 0
3 years ago
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What is 645/87 rounded to the nearest integer?
Vlad1618 [11]

Answer:

7

Step-by-step explanation:

Firstly, let us divide the two numbers as so-

645/87=7.41379310345\\

To round a number to the nearest integer, look at the decimal places.

Here we have .41 - The 4 is less than 5, so it cannot round the ones place to 8.

So our answer here is 7.

6 0
2 years ago
Halle solved 664/48 below. She got a quotient of 13 with a remainder of 40. How could she solve 659/48 without redoing the work?
Lerok [7]
She should multiply the quotient by 48.
3 0
3 years ago
How to solve this plss frac{(\sqrt{(3)})^{5}}{((\sqrt{(3)})^{-4})}=(\sqrt{(3)})^{(2k+1)​
dusya [7]

Answer:

k = 4

Step-by-step explanation:

Given equation:

\dfrac{(\sqrt{3})^{5}}{(\sqrt{3})^{-4}}=(\sqrt{3})^{(2k+1)}

\textsf{Apply exponent rule} \quad \dfrac{a^b}{a^c}=a^{b-c}:

\implies (\sqrt{3})^{(5-(-4))}=(\sqrt{3})^{(2k+1)}

\implies (\sqrt{3})^{9}=(\sqrt{3})^{(2k+1)}

\textsf{Apply exponent rule} \quad a^{f(x)}=a^{g(x)} \implies f(x)=g(x):

\implies (\sqrt{3})^{9}=(\sqrt{3})^{(2k+1)}

\implies 9=2k+1

\implies 2k=8

\implies k=4

6 0
2 years ago
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