I really have no idea where to start with this. Could someone please exaplin the answer and how they got it? Theres a lot of the
se on my thing and I'd like to understnad it so that I can do the others on my own. Teachers aren't in office today so I can't ask for help :'(
Thankyou!!
Thankyou!!
2 answers:
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Answer:
The magnitude of the magnetic force acting on the conductor is 0.75 Newton
Explanation:
The parameters given in the question are;
The length of the straight segment of wire, L = 25 cm = 0.25 m
The current carried in the wire, I = 5 A
The orientation of the wire with the magnetic field = Perpendicular
The strength of the magnetic field in which the wire is located, B = 0.60 T
The magnetic force, 'F', is given by the following formula;
F = ·L×
= I·L·B·sin(θ)
Where;
= The current flowing, I
L = The length of the wire
= The magnetic field strength, B
θ = The angle of inclination of the conductor to the magnetic field
Where I = 5 A, L = 0.25 m, B = 0.60 T, and θ = 90°, we get;
F = 5 A × 0.25 m × 0.60 T × sin(90°) = 0.75 N
Therefore
The magnitude of the magnetic force, F = 0.75 N.
Answer:
The moment is 81.102 k N-m in clockwise.
Explanation:
Given that,
Force = 260 N
Side = 580 mm
Distance h = 370 mm
According to figure,
Position of each point
We need to calculate the position vector of AB
We need to calculate the unit vector along AB
We need to calculate the force acting along the edge
We need to calculate the net moment
Put the value into the formula
Put the value into the formula
Negative sign shows the moment is in clockwise.
Hence, The moment is 81.102 k N-m in clockwise.
Answer:
the decrease in energy is due to a transformational in internal energy of the body in the rebound.
Explanation:
For this exercise we can calculate the initial and final mechanical energy
Em₀ = U = m g y₁
= U = m g y₂
we look for the variation of the energy
ΔEm = Em_{f} - Em₀
ΔEm = m g (y_{f} -y₀)
ΔEm = m g (0.86 -1.2)
ΔEm = -3.332 m
We can see that there is a decrease in mechanical energy, this is transformed into internal energy of the ball during the impact with the ground, this energy can be formed by several factors such as a part of the friction with the surface, an increase in body temperature or a deformation of the body; there may be a contribution from several of these factors.
In conclusion the decrease in energy is due to a transformational in internal energy of the body in the rebound.