Answer:
1 second later the vehicle's velocity will be:
5 seconds later the vehicle's velocity will be:
Explanation:
Recall the formula for the velocity of an object under constant accelerated motion (with acceleration "
"):
Therefore, in this case 
and 
so we can estimate the velocity of the vehicle at different times just by replacing the requested "t" in the expression:
Answer:
V = 6.53 × 10^14
h = 6.626 × 10^-34
E = hV
E = (6.626 × 10^-34) (6.53 × 10^14)
E = 4.33 × 10^-19
Answer:
20 kg*m/s
Explanation:
we're looking for the change in the cars momentum . the formula to identify the cars momentum is Δp=m*vf-m*vi . In this case m= mass , vf= velocity final, and vi= velocity initial . The mass is how much the car weighs , which is 4 kg . Velocity final would be 8 m/s since that's how fast it last was . Velocity initial would be 3 m/s since it had first started at that speed . Now we can jus plug it into the formula .
m= 4 kg
vf= 8 m/s
vi= 3 m/s
Δp= (4)*(8) - (4)*(3)
Δp= 32-12
Δp= 20 kg*m/s
hope this helps .
Kinetic energy (K.E) = 1/2 mass x velocity²
Momentum (P) = mass x velocity
K.E = 1/2 Pv
233 = 1/2 x 20.4 x v
v = 22.8 m/s
20.4 = 22.8m
m = 0.89 kg
