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adelina 88 [10]
3 years ago
5

Which of the following happens when unbalanced forces act on an object? The object remains stationary. The object moves with the

same velocity. The object moves in the direction of the stronger force. The object's speed and direction of motion remain unchanged
Physics
2 answers:
kvasek [131]3 years ago
8 0
The object move in the direction of the stronger force
BlackZzzverrR [31]3 years ago
7 0

Answer:

The correct answer would be C  The object moves in the direction of the stronger force.

Explanation:

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A student places his hand in front of a plane mirror as shown in the diagram. Which terms correctly describe the image that the
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Two +1 C charges are separated by 30000 m, what is the magnitude of<br> the force?
Kipish [7]

Answer:

<em>The magnitude of the force is 10 N</em>

Explanation:

<u>Coulomb's Law</u>

The electrostatic force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Written as a formula:

\displaystyle F=k\frac{q_1q_2}{d^2}

Where:

k=9\cdot 10^9\ N.m^2/c^2

q1, q2 = the objects' charge

d= The distance between the objects

We have two identical charges of q1=q2=1 c separated by d=30000 m, thus the magnitude of the force is:

\displaystyle F=9\cdot 10^9\frac{1*1}{30000^2}

\displaystyle F=9\cdot 10^9\frac{1*1}{30000^2}

F = 10 N

The magnitude of the force is 10 N

7 0
3 years ago
A 1.5m wire carries a 6 A current when a potential difference of 68 V is applied. What is the resistance of the wire?
ANTONII [103]

Answer:

11.3 \Omega

Explanation:

We can find the resistance of the wire by using Ohm's law:

V=RI

where

V is the voltage applied

R is the resistance

I is the current

In this problem, we know I = 6 A and V = 68 V, so we can re-arrange the equation to find the resistance of the wire:

R=\frac{V}{I}=\frac{68 V}{6 A}=11.3 \Omega

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Hiii !!!
I am sending the soluction !!!

If you have any question, let me now =)

Jorge:)

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