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adelina 88 [10]
3 years ago
5

Which of the following happens when unbalanced forces act on an object? The object remains stationary. The object moves with the

same velocity. The object moves in the direction of the stronger force. The object's speed and direction of motion remain unchanged
Physics
2 answers:
kvasek [131]3 years ago
8 0
The object move in the direction of the stronger force
BlackZzzverrR [31]3 years ago
7 0

Answer:

The correct answer would be C  The object moves in the direction of the stronger force.

Explanation:

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The question is on the picture
Firlakuza [10]

Answer:

<em> think 2 also if not im so sorry  but i think it is :)</em>

7 0
2 years ago
If your Stronger than Hisoka, and you know it, Clap your hands! Oh, wait.. That’s right! You don’t have any hands. Lol
ddd [48]

Answer:

Haha pretty funny

Explanation:

3 0
2 years ago
Read 2 more answers
An object is moving along the x axis. At t = 5.6 s, the object is at x = +3.0 m and has a velocity of +5.7 m/s. At t = 8.5 s, it
Debora [2.8K]

The average acceleration between t = 5.6 s and t = 8.5 s is 2.31  m/s²

<h3>What is acceleration?</h3>

Acceleration is defined as the rate change of velocity with time.

acceleration a = (Δv) / (Δt)

An object is moving with initial velocity u =5.7 m/s and its final velocity v= -1.0 m/s.

Time taken for the change in speed, t= 8.5 - 5.6 = 2.9 seconds

The acceleration is given by

a = (-1 - 5.7)/ 2.9

a = -  2.31 m/s²

|a | = 2.31 m/s²

Thus, the object's acceleration is 2.31 m/s²

Learn more about acceleration.

brainly.com/question/12550364

#SPJ1

3 0
2 years ago
Two 110 kg bumper cars are moving toward each other in opposite directions. Car A is moving at 8 m/s and Car Z at –10 m/s when t
julsineya [31]

This is a conservation of momentum problem! Here's how to do it:

6 0
3 years ago
A 13-kg sled is moving at a speed of 3.0 m/s. At which of the following speeds will the sled have twice as much kinetic energy?
AysviL [449]
K.E. = 1/2 mv²
K.E. is directly proportional to v^2
So, when K.E. increase by 2, K.E. increase by root. 2
v' = 1.41v
original v value was 3 so, final would be:
v' = 1.41*3 = 4.23
After round-off to it's tenth value, it will be:
v' = 4.2

So, option B is your answer!

Hope this helps!

7 0
3 years ago
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