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3 years ago

As a ball falls freely toward the ground, its total

1 answer:

hjlf3 years ago

3 0

As a ball falls freely toward the ground, its total <span>mechanical energy "remains the same" but it should be noted that its potential energy is decreases at this time. </span>

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A plane traveling horizontally at 120 m/s over flat ground at an elevation of 3610 m must drop an emergency packet on a target

allsm [11]

Answer:

Explanation:

Horizontal displacement

x = 120 t

Vertical position

y = 3610 - 4.9 t²

y = 0 for the ground

0 = 3610 - 4.9 t²

t = 27.14 s

This is the time it will take to reach the ground .

During this period , horizontal displacement

x = 120 x 27.14 m

= 3256.8 m

So packet should be released 3256.8 m before the target.

3 0

3 years ago

Read 2 more answers

Hi please, I Have An attachment on Waves, Just two Objective Questions Whoever Answers Will be Marked Brainliest thank you.

kifflom [539]

Answer:

The first answer is W and Z, since they appear to be a period apart. Dont know the second question. I did what I could, hope someone can answer the second.

5 0

3 years ago

A long. 1.0 kg rope hangs from a support that breaks, causing the rope to fall, if the pull exceeds 43 N. A student team has bui

raketka [301]

Answer:

6.8 m/s2

Explanation:

Let g = 9.8 m/s2. The total weight of both the rope and the mouse-robot is

W = Mg + mg = 1*9.8 + 2*9.8 = 29.4 N

For the rope to fails, the robot must act a force on the rope with an additional magnitude of 43 - 29.4 = 13.6 N. This force is generated by the robot itself when it's pulling itself up at an acceleration of

a = F/m = 13.6 / 2 = 6.8 m/s2

So the minimum magnitude of the acceleration would be 6.8 m/s2 for the rope to fail

8 0

3 years ago

A stone is thrown into a well and the splash is heard after 3s. (speed of sound : 340m/s) . 1.) What time did the stone take to

miss Akunina [59]

1.)3s
2.)6s
3.)1020m

hope this help

8 0

3 years ago

A wall with a surface area of 10 m2 is 2.5 cm thick. The inner surface temperature of the wall is 4150C, but the outer surface i

klio [65]

Answer:

650.65 K or 377.5°C

Explanation:

Area = A = 10 m²

Thickness of wall = L = 2.5 cm = 2.5×10⁻² m

Inner surface temperature of wall = $T_i$ = 415°C = 688.15 K

Outer surface temperature of wall = $T_o$

Heat loss through the wall = 3 kW = 3×10³ W

Thermal conductivity of wall = k = 0.2 W/m K

Assumptions made here as follows

There is not heat generation in the wall itself
The heat conduction is one dimensional
Heat flow follows steady state
The material has same properties in all directions i.e., it is homogeneous.

Considering the above assumptions we use the following formula

$Q=\frac {T_i-T_o}{\frac{L}{kA}}\\\Rightarrow T_o=T_i-\frac {QL}{kA}\\\Rightarrow T_o=688.15-\frac {3\times 10^{3}\times 2.5\times 10^{-2}}{0.2\times 10}\\\Rightarrow T_o=650.65~K$

∴ The temperature of the outer surface of the wall is 650.65 K or 377.5°C

5 0

4 years ago