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3 years ago

As a ball falls freely toward the ground, its total

1 answer:

hjlf3 years ago

3 0

As a ball falls freely toward the ground, its total mechanical energy "remains the same" but it should be noted that its potential energy is decreases at this time.

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A bird carrying a fish (5kg) drops it from 107 meters in the air how fast does the fish hit the ground

notka56 [123]

Answer:

The velocity of the fish hitting the ground is , v = 45.795 m/s

Explanation:

Given data,

The mass of the fish, m = 5 kg

The height of the bird from the surface, h = 107 m

Using the III equation of motion,

v² = u² + 2gs

v = √(u² + 2gs)

Substituting the values,

v = √(0² + 2 x 9.8 x 107)

= 45.795 m/s

Hence, the velocity of the fish hitting the ground is, v = 45.795 m/s

4 0

3 years ago

A ball is dropped off the side of a bridge. After 1.55 s, how far has it fallen?

KengaRu [80]

Answer:11.7 meters

Explanation: Gravitational acceleration (g)

9.8 m/s²

Initial velocity (v₀)

0 ft/s

Height (h)

11.77225 m

Time of fall (t)

1.55 sec

Velocity (v)

15.19 m/s

6 0

3 years ago

The towel has better blank

koban [17]

Answer:

Explanation:

Towels Absorb

5 0

3 years ago

For a wire has a circular cross section with a radius of 1.23mm.

Mila [183]

Answer:

$5.731\times 10^{-5}\ m/s$

Decrease

Explanation:

I = Current = 3.7 A

e = Charge of electron = $1.6\times 10^{-19}\ C$

n = Conduction electron density in copper = $8.49\times 10^{28}\ electrons/m^3$

$v_d$ = Drift velocity of electrons

r = Radius = 1.23 mm

Current is given by

$I=neAv_d\\\Rightarrow v_d=\dfrac{I}{neA}\\\Rightarrow v_d=\dfrac{3.7}{8.49\times 10^{28}\times 1.6\times 10^{-19}\times \pi (1.23\times 10^{-3})^2}\\\Rightarrow v_d=5.731\times 10^{-5}\ m/s$

The drift speed of the electrons is $5.731\times 10^{-5}\ m/s$

$v_d=\dfrac{I}{neA}$

From the equation we can see the following

$v_d\propto \dfrac{1}{n}$

So, if the number of conduction electrons per atom is higher than that of copper the drift velocity will decrease.

5 0

3 years ago

What two factors are a part of thermohaline circulation

Margarita [4]

Answer:

These deep-ocean currents are driven by differences in the water's density, which is controlled by temperature (thermo) and salinity (haline). This process is known as thermohaline circulation.

Explanation:

7 0

3 years ago