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Valentin [98]
3 years ago
6

The near point of a farsighted person's uncorrected eyes is 80 cm. what power contact lens should be used to move the near point

to 25 cm from this person's eyes?
Physics
1 answer:
makvit [3.9K]3 years ago
5 0
To solve this problem, we will get f and then we will use it to calculate the power.

So, for this farsighted person,
do = 25 cm and di = -80
Therefore:
1/f = (1/25) + (1/-80) = 0.00275 = 0.275 m

Power = 1/f = 1/0.275 = +3.6363 Diopeters.
This means that the lens is converging.
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If the frequency of an electromagnetic wave increases, does the number of waves passing by you increase, decrease, or stay the s
jarptica [38.1K]

Answer:

option(d)

Explanation:

The frequency of a wave is the property of the source of wave.

The velocity of all the electromagnetic waves is same as the speed of light. It only changes as the light passes through one medium to another.

The frequency is defined as the number of waves coming out from the source in 1 second.

As the frequency of wave increases, the number of wave coming per second increases.

So, the number of waves passing by increases but the speed remains same.

Option (d)

3 0
3 years ago
1. A 2500 kg car enters a curve with a radius of 45 m If the car is moving at a speed of 35 m's, what is the
Aleonysh [2.5K]

Answer:

Banana Splits with tomatoes sauce on top (but no ketchup or Mustard) in my knee with a Balenciaga private jet.

Explanation:

There is no Explanation. Look at the answer.

3 0
3 years ago
a 5.0-ft woman wishes to see a full length image of herself. what is the minimum length mirror required?​
nadezda [96]

Answer:

2.5 ft

Explanation:

minimum size of the mirror should be one half the person's height.

For this woman of 5 feet height, she would therefore need a mirror of length 2.5 feet

5ft ÷ 2 ft (half) = 2.5ft OR half of 5t is 2.5ft

4 0
1 year ago
A 2100 kg car starts from rest and accelerates at a rate of 2.6 m/s2 for 4.0 s. Assume that the force acting to accelerate the c
Reika [66]
When the system is experiencing a uniformly accelerated motion, there are a set of equations to work from. In this case, work is energy which consist solely of kinetic energy. That is, 1/2*m*v2. First, let's find the final velocity.

a = (vf - v0)/t
2.6 = (vf - 0)/4
vf = 10.4 m/s

Then W = 1/2*(2100 kg)*(10.4 m/s)2
W = 113568 J = 113.57 kJ
8 0
3 years ago
An electric motor rotating a workshop grinding wheel at 1.06 102 rev/min is switched off. Assume the wheel has a constant negati
kvasek [131]

Answer:

t = 106π / 30*2.1

Explanation:

w_{i} = 1.06*10^{2}    => 106

    => 106 x 2π/60

    => 106/30π

∝ = -2.1 rad/sec²

w_{f} => 0

w_{f} = w_{i} + ∝t

∴ (w_{f} - w_{i}) / ∝ = t

t = 106π / 30*2.1

6 0
3 years ago
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