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miss Akunina [59]
3 years ago
7

A toy rocket launched straight up from the ground with an initial velocity of 80 ft/s returns to the ground after 5 s. The heigh

t of the rocket t seconds after launch is modeled by the function f(t)=−16t2+80t . What is the maximum height of the rocket, in feet?
Mathematics
2 answers:
eimsori [14]3 years ago
6 0
Maximum is 100
I just took the test, got it right 
mixas84 [53]3 years ago
5 0

Answer:

Maximum height oh the rocket was 100 feet.

Step-by-step explanation:

It has been given in the question that rocket follows the function f(t) = 80t-16t² where t is the time taken by rocket to reach maximum height and coming back to the ground.

Since initial velocity of the rocket is = 80 ft/sec

and total time taken by the rocket to come back to the ground is 5 sec

time taken by the rocket to reach the maximum height = 5/2 = 2.5 sec

Therefore from the given function

Maximum height achieved by the rocket = 80.(2.5) - 16.(2.5)²

= 200 - 100 = 100 ft.

 

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The length of a rectangle is seven inches more than its width. Its area is 78 square inches. Find the width and length of the re
Alekssandra [29.7K]

Answer:

Length: 23.38

Width: 3.34

Step-by-step explanation:

First I drew out a diagram so that I could visibly see the problem. [ a rectangle with 7x on one side and x on the other.

So to find the area you multiply length time width and 7x times x is 7x^2. The actual area is given: 78, so you set that equal to 7x^2.

Then you want to divide by 7 to get 11.14. Then you want to take the square root of 11.14 to get 3.338 which rounds to 3.34 {try not to round until the very end]. This gives you the width of the rectangle, so to find the length you would have to multiply x by 7 to get 23.38. When you multiply the length and width (3.34 x 23.38) you get 78.08 which can round to 78.

7x^2 = 78

x^2 = 78/7

x^2= 11.142...

x = sqrt(1.142...)

x = 3.338 --> 3.34 --> width

3.34 x 7 --> 23.38 --> length

3.34 x 23.38 --> 70.8

8 0
3 years ago
Read 2 more answers
Ecuacion de parabola con foco (-2,5) directriz en x=3
Dmitry_Shevchenko [17]

The required equation of the parabola is (y-5)² = 20(x+2)

<h3>Equation of a parabola</h3>

The standard equation of a parabola is expressed as;

(y-k)² = 4p(x-h)

where;

vertex = (h, k)

focus = (p+k, k)

directrix x = -p + h

Note that the directrix given will determine the type of the equation of a parabola

Given the following parameters

focus = (-2, 5) = (h, k)

x = -p + h

3 = p -2

p = 5

Substitute

(y-k)² = 4p(x-h)

(y-5)² = 4(5)(x-(-2))

(y-5)² = 20(x+2)

Hence the required equation of the parabola is (y-5)² = 20(x+2)

Learn more on equation of parabola here; brainly.com/question/4061870

#SPJ1

6 0
2 years ago
How many rotations does each wheel make while Shawn is coasting down the ramp?
____ [38]
I think it’s 16 rotations
3 0
3 years ago
Read 2 more answers
Subtract the sum of 3y+7 and 5y-7 from4y-5
ivolga24 [154]
(3y + 7) + (5y-7)= 8y

(4y - 5)- 8y= -4y-5
4 0
3 years ago
Twenty less than the product of 3 and a number is -29. What is the number?
son4ous [18]

Answer:

-3

Step-by-step explanation:

3*-3=-9

-9-20=-29

3 0
3 years ago
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