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Natasha2012 [34]
4 years ago
13

Write the ions present in a solution of na3po4.

Chemistry
1 answer:
Doss [256]4 years ago
6 0
The ions present in the solution of Na₃PO₄ are:
3Na⁺¹ and 1PO₄⁻³
 there are 3 sodium ions (Na⁺¹) are present, these are cations (+).
And 1 phosphate ion (PO₄⁻³) is present, this is anion (-),
When these cations and ions meet together a compound is formed, in this case 3 sodium ions make a bond with 3 oxygens of phosphate and makes a compound of sodium phosphate.
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4 years ago
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3 years ago
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3 years ago
If 4.0 mol of NO and 4.0 mol of O2 are combined, how many moles
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4.0


i think it has something to do with molar ratios and finding the limiting reactant

4.0 mol NO * 2 mol NO2/2 mol NO = 4.0 moles of NO2

4.0 mol O2 * 2 mol NO2/1 mol O2 = 8.0 moles of NO2

so the limiting reactant (the reactant that runs out the quickest leaving an excess) is NO

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4 0
3 years ago
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