Answer:
C. They are exergonic and provide energy that can be used to produce ATP form ADP and Pi.
Explanation:
There are 2 types of metabolic reactions.
- Anabolic reactions (Anabolism)
- Catabolic reactions (Catabolism)
CATABOLIC REACTIONS:
They consist of reactions in which larger molecules are broken down into simpler ones. They are exergonic i.e. energy producing reactions. The released energy can be stored in the form of ATP (energy currency of cell).
ANABOLIC REACTIONS:
They consist of reactions in which larger molecules are synthesized from simpler ones. They are endergonic reactions i.e. energy is absorbed.
MEMORY AID:
An easy way to remember catabolic reactions is to think of them as "catastrophic reactions" i.e. larger molecules are destructed to produce simpler ones.
Coming back to the question,
<u>a. They require energy from ATP hydrolysis to break down polymers into monomers. </u>
Energy requiring reactions are anabolic and so this is the incorrect answer.
<u>b. They are endergonic and release energy that can be used for cellular work.</u>
Endergonic reactions are anabolic and hence this is the incorrect answer.
<u>c. They are exergonic and provide energy that can be used to produce ATP from ADP and Pi</u>
This statement correctly fits the definition of Catabolic reactions and is therefore the correct answer.
<u>d. They combine small molecules into larger, more energy-rich molecules.</u>
This statement describes anabolic reactions and hence the incorrect choice.
Answer:
10.5L
Explanation:
The volume in this question can be calculated by using the formula for gas law equation as follows:
PV = nRT
Where;
P = pressure (atm)
V = volume (litres)
n = number of moles (mol)
R = gas law constant (0.0821 Latm/molK)
T = temperature (K)
According to the provided information in this question:
P = 6.18 atm
V = ?
n = 2.35 moles
R = 0.0821 Latm/molK
T = 63°C = 63 + 273 = 336K
Using PV = nRT
V = nRT/P
V = 2.35 × 0.0821 × 336/ 6.18
V = 64.83/6.18
V = 10.49
V = 10.5L
Answer:
Do you just want to talk?
Explanation:
Do you need help with anything?
Answer:
The volume (mL) of 0.135 M NaOH that is required to neutralize 13.7 mL of 0.129 M HCl is 13.1 mL (option b).
Explanation:
The reaction between an acid and a base is called neutralization, forming a salt and water.
Salt is an ionic compound made up of an anion (positively charged ion) from the base and a cation (negatively charged ion) from the acid.
When an acid is neutralized, the amount of base added must equal the amount of acid initially present. This base quantity is said to be the equivalent quantity. In other words, at the equivalence point the stoichiometry of the reaction is exactly fulfilled (there are no limiting or excess reagents), therefore the numbers of moles of both will be in stoichiometric relationship. So:
V acid *M acid = V base *M base
where V represents the volume of solution and M the molar concentration of said solution.
In this case:
- V acid= 13.7 mL= 0.0137 L (being 1,000 mL= 1 L)
- M acid= 0.129 M
- V base= ?
- M base= 0.135 M
Replacing:
0.0137 L* 0.129 M= V base* 0.135 M
Solving:
V base=0.0131 L = 13.1 mL
<u><em>
The volume (mL) of 0.135 M NaOH that is required to neutralize 13.7 mL of 0.129 M HCl is 13.1 mL (option b).</em></u>
