Answer:
C4H6 + 2HBr = C4H8Br2
Explanation:
Alkynes are organic molecules made of the functional group carbon-carbon triple bonds and are written in the empirical formula of CnH2n−2. They are unsaturated hydrocarbons.
Furthermore, Halogenation reaction of any alkyne such as but-2-yne with any of the hydro halogenated compounds such as HBr, HCl, HF or HI will give an alkane that will have the same number of carbon atoms in the starting material and in the final product.
Halogenation reaction is a reaction that occurs when one or more halogens are added to a substance. Halogens is the seventh column in the periodic table and it include fluorine, chlorine, bromine, iodine, and astatine.
The halogens and noble gases are alike because they are all non-metallic elements, with the exception of astatine, a radioactive
Answer:
1.8 × 10⁻⁴ mol M/s
Explanation:
Step 1: Write the balanced reaction
2 Br⁻ ⇒ Br₂
Step 2: Establish the appropriate molar ratio
The molar ratio of Br⁻ to Br₂ is 2:1.
Step 3: Calculate the rate of appearance of Br₂
The rate of disappearance of Br⁻ at some moment in time was determined to be 3.5 × 10⁻⁴ M/s. The rate of appearance of Br₂ is:
3.5 × 10⁻⁴ mol Br⁻/L.s × (1 mol Br₂/2 mol Br⁻) = 1.8 × 10⁻⁴ mol Br₂/L.s
Answer:
P2≈393.609Kpa so I think the answer is 394 kPa
Explanation:
PV=mRT Ideal Gas Law
m and R are constant because they dont change for the problem. That means
PV/T=mR = constant
so P1*V1/T1=P2*V2/T2 and note that the temperatures are in absolute temperatures (Kelvin) because you can't divide by zero.
So P2 = P1*V1*T2/(V2*T1) = 101325 Pa * 700 mL * 303K/(200 mL*273K)
P2 = 393609 Pa
