Answer:
100 mL
Explanation:
Given data:
Mass of CaCO₃ produced = 2.00 g
Molarity of CaCl₂ = 0.200 M
Volume of CaCl₂ needed = ?
Solution:
Chemical equation:
Na₂CO₃ + CaCl₂ → 2NaCl + CaCO₃
First of all we will calculate the number of moles of CaCO₃.
Number of moles = mass/molar mass
Number of moles = 2.00 g / 100.09 g/mol
Number of moles = 0.02 mol
Now we will compare the moles of CaCO₃ and CaCl₂.
CaCO₃ : CaCl₂
1 : 1
0.02 : 0.02
Thus, 0.02 moles of CaCl₂ react,
Volume of CaCl₂ reacted:
Molarity = number of moles / volume in L
0.200 M = 0.02 mol / volume in L
Volume in L = 0.02 mol / 0.200 M
Volume in L = 0.1 L
Volume in mL:
0.1 L × 1000 mL/1L
100 mL
Answer:
Quartenary.
Explanation:
Quaternary ammonium compounds (QACs) are cationic salts of organically substituted ammonium compounds and have a broad range of activity against microorganisms, i.e more effective against Gram-positive bacterium at lower concentrations than Gram-negative bacteria.
It was also reported previously that monoalkyl QACs bind by ionic and hydrophobic interactions to microbial membrane surfaces, with the cationic head group facing outwards and the hydrophobic tails inserted into the lipid bilayer, causing the rearrangement of the membrane and the subsequent leakage of intracellular constituents.
The relative humidity of the air is the ratio of the actual amount of moisture in the air to the fully saturated amount. There for the answer is 33.1% or 3.3g/kg
