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2 years ago

Explain the role of each factor in chemical weathering (water, acid, and air).

Chemistry

2 answers:

Mama L [17]2 years ago

7 0

Answer: hydrolysis oxidation acidification

Explanation:

they break down, dissolve, or create new elements

rjkz [21]2 years ago

4 0

Chemical weathering affects hillslope form by directly removing mass from hillslopes. The transformation of primary minerals to secondary minerals can also affect the hydrology, biota, and stability of hillslopes, which in turn influence sediment transport and landscape morphology. Erosion in evolving landscapes can modulate and be modulated by chemical weathering; for example, pulses of accelerated erosion can lower the residence time of hillslope materials, thereby increasing their chemical weathering rates, which in turn accelerate the incision signal.

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Habitat destruction of the ecosystem.

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3 years ago

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A solution was made by dissolving 5.10 mg of hemoglobin in water to give a final volume of 1.00 ml. the osmotic pressure of this

Assoli18 [71]

The molecular weight of hemoglobin can be calculated using osmotic pressure

Osmotic pressure is a colligative property and it depends on molarity as

πV = nRT

where

π = osmotic pressure

V = volume = 1mL = 0.001 L

n = moles

R = gas constant = 0.0821 L atm / mol K

T = temperature = 25°C = 25 + 273 K = 298 K

Putting values we will get value of moles

$moles=\frac{\pi V}{RT}=\frac{0.00195X0.001}{0.0821X298}mol$

we know that

$moles=\frac{mass}{molarmass}$

Therefore

$molarmass=\frac{mass}{moles}=\frac{5.10X10^{-3}g}{7.97X10^{-8}}=6.399X10^{4}g$

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3 years ago

How many atoms are in 1.50 moles of fluorine gas

evablogger [386]

1.8x10^24 atoms is How many atoms are in 1.50 moles of fluorine gas

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3 years ago

The figure above shows the Earth at two different positions in its orbit around the Sun. Which position corresponds to summer in

Lelu [443]

Answer:

A. Position B.

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In the summer the northern hemisphere is closer to the Sun so it's Position B.

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What is the percent ionization of a 1.8 M HC2H3O2 solution (Ka = 1.8 10-5 ) at 25°C?

xz_007 [3.2K]

Answer:

B) 0.32 %

Explanation:

Given that:

$K_{a}=1.8\times 10^{-5}$

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$\begin{matrix}&CH_3COOH&\rightleftharpoons &CH_3COOH&+&H^+\\ At\ time, t = 0 &1.8&&0&&0\\At\ time, t=t_{eq}&-x&&+x&&+x\\ ----------------&-----&-&-----&-&-----\\Concentration\ at\ equilibrium:-&1.8-x&&x&&x\end{matrix}$