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3 years ago

Calcium and sulfur Enter the ions formed by these elements and separate your answers with a comma (e.G., Sr2+,As3−).

Chemistry

1 answer:

iogann1982 [59]3 years ago

4 0

Answer:

Ca²⁺, S⁻²

Explanation:

Calcium (Ca) is a metallic element and belongs to group II of the Periodic Table. So, it can lose 2 electrons to form the positively charged ion Ca²⁺.

Sulfur (S) is a non-metal element, so it has the tendency to gain electrons and to form anions. It accepts two electrons to form the sulfide ion S²⁻.

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If a 1.00 mL sample of the reaction mixture for the equilibrium constant experiment required 32.40 mL of 0.258 M NaOH to titrate

andrey2020 [161]

Answer:

The concentration of acetic acid is 8.36 M

Explanation:

Step 1: Data given

Volume of acetic acid = 1.00 mL = 0.001 L

Volume of NaOH = 32.40 mL = 0.03240 L

Molarity of NaOH = 0.258 M

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate the concentration of the acetic acid

b*Ca*Va = a*Cb*Vb

⇒with b = the coefficient of NaOH = 1

⇒with Ca = the concentration of CH3COOH = TO BE DETERMINED

⇒with Va = the volume of CH3COOH = 1.00 mL = 0.001L

⇒with a = the coefficient of CH3COOH = 1

⇒with Cb = the concentration of NaOH = 0.258 M

⇒with Vb = the volume of NaOH = 32.40 mL = 0.03240 L

Ca * 0.001 L = 0.258 * 0.03240

Ca = 8.36 M

The concentration of acetic acid is 8.36 M

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An analytical chemist has determined by measurements that there are 96.5 moles of carbon in a sample of acetic acid. how many mo

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Therefore, the sample that contains 96.5 moles of carbon, will contain also 96.5 moles of O.

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