Answer:
There will be 0.825 grams of CO2 produced
Explanation:
Step 1: Data given
Mass of water formed = 0.45 grams
Molar mass of water = 18.02 g/mol
Molar mass of CO2 = 44.01 g/mol
Step 2: The balanced equation
C3H8 + 5O2 → 4H2O + 3CO2
Step 3: Calculate moles of water
Number of moles water = mass of water / molar mass water
Number of moles water = 0.45 grams / 18.02 g/mol
Number of moles water = 0.025 moles
Step 4: Calculate moles of CO2
For 1 mol of propane we need 5 moles of O2 to produce 4 moles of H2O and 3 moles of CO2
When 0.025 moles of H2O are produced, we'll get 3/4 * 0.025 = 0.01875 moles of CO2 produced
Step 5: Calculate mass of CO2 produced
Mass of CO2 = moles of CO2 * molar mass of CO2
Mass of CO2 = 0.01875 moles * 44.01 g/mol
Mass of CO2 = 0.825 grams
There will be 0.825 grams of CO2 produced
Answer: 245 L
Explanation:-
To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.
The equation given by this law is:
![P_1V_1=P_2V_2](https://tex.z-dn.net/?f=P_1V_1%3DP_2V_2)
where,
are initial pressure and volume.
are final pressure and volume.
We are given:
![P_1=23.0atm\\V_1=16.0L\\P_2=1.50atm\\V_2=?](https://tex.z-dn.net/?f=P_1%3D23.0atm%5C%5CV_1%3D16.0L%5C%5CP_2%3D1.50atm%5C%5CV_2%3D%3F)
Putting values in above equation, we get:
![23.0\times 16.0=1.50\times V_2\\\\V_2=245L](https://tex.z-dn.net/?f=23.0%5Ctimes%2016.0%3D1.50%5Ctimes%20V_2%5C%5C%5C%5CV_2%3D245L)
Thus new volume of gas is 245 L
It’s wave motion. Because when wave passes throug an object, some of the other material can go though on other object(s).
Answer:
[A] = 1.438M = 1.4M (Two s.f)
Explanation:
Rate constant, k = 0.00317
Initial Concentration, [A]o = 1.44M
Final Concentration, [A] = ?
Time, t = 0.240 s
Since this is a second order reaction, the formula for this is given as;
1 / [A] = 1 / [A]o + kt
1 / [A] = 1 / 1.44 + (0.00317 * 0.240)
1 / [A] = 0.6944 + 0.0007608
1 / [A] = 0.6952
[A] = 1.438M = 1.4M (Two s.f)