S(t) = sin(πt/6) + cos(πt/6)
Velocity = s'(t) = π/6 (cos(πt/6) - sin(πt/6))
When velocity = 0
cos(πt/6) - sin(πt/6) = 0
cos^2(πt/6) -2cos(πt/6) sin(πt/6) + sin^2(πt/6) = 0
1 - 2cos(πt/6) sin(πt/6) = 0
1 - sin(πt/3) = 0
sin(πt/3) = 1
πt/3 = arcsin(1) = π/2
t = 1.5
acceleration = s''(t) = -(π/6)^2 (cos(πt/6) + sin(πt/6))
s''(1.5) = -(π/6)^2 (cos(π/4) + sin(π/4)) = -(π/6)^2 (2/√2) = -0.3877
accerelation = -0.3877 meter/s^2
Answer:
i very diffucult question
Answer:
undefined slope
Step-by-step explanation:
There us change in rise but no change in run or x value. This means is a vertical line and it's slope is undefined.
Answer:
-x
Step-by-step explanation:
8x - 9x
Factor out an x
x(8-9)
x (-1)
-x
