Answer:
0.22M
Explanation:
We will be using the law of dilutions. We are simply increasing the amount of solvent to create a larger volume of solution.
So: moles before dilution = moles after dilution &
. And M = moles/liter of solution, so if we express this as moles = M x
.
That is how we derive the formula we will be using: 
or

Applying this formula to our problem, we can substitute the variables with the given values to find the molarity of the dilute solution.
M1 = 3.5M
V1 = 18.8mL
M2 = ?
V2 = 296.6mL
Equation: (3.5M)(18.8mL) = (296.6mL)(M2)
==> 65.8M*mL = 296.6mL * M2
==> M2 = (65.8 M*mL)/296.6mL
==> M2 = 0.22M
Answer: -
71
Explanation: -
From the diagram, we see that volume goes from 70 to 75 in 5 markings.
Each marking is for 1.
It is the most accuracy possible as there is no smaller marking.
Significant figures expresses the required amount of accuracy.
Thus the volume indicated from the diagram is 71 .
Answer:
4.5 M
Explanation:
70.0 ml was mixed in 3.00 M of Na2SO4
30.0 ml was mixed in 1.00 M of NACL
The first step is to convert 70 ml to liters
= 70/1000
= 0.07 liters
The formular for molarity is
moles/liters
The number of moles in Na2S04 can be calculated as follows
Let y represent the number of moles
3M= y moles/0.07
= 3×0.07
= 0.21 moles
Since Na2So4 has 2 moles of Na then the number of moles is
= 2×0.21
= 0.42 moles
Convert 30ml to liters
= 30/1000
= 0.03 liters
The number of moles in Nacl can be calculated as follows
Let y represent the number of moles
1M= y moles/0.03
= 1×0.03
= 0.03 moles
Since Nacl has 1 mole of Na then the number of moles is
= 1 × 0.03
= 0.03 moles
Therefore the final Na+ can be calculated as follows
Total moles = 0.03 moles + 0.42 moles
= 0.45 moles
Total liters= 0.07 liters + 0.03 liters
= 0.1 liters
Na+ = 0.45/0.1
= 4.5 M
Hence the final Na+ in the solution is 4.5 M
The word mole is one of those crazy words that have multiple meanings that can sometimes lead to confusion. Perhaps your first thought after hearing the word is a cute little animal that burrows in the ground.
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