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3 years ago

What can the vast majority of elements in the periodic table be classified?

2 answers:

8 0

One useful way is by metals, nonmetals, and metalloids. (See also The Periodic Table: Families and Periods.) Most of the elements on the periodic table are classified as metals.

Bess [88]3 years ago

7 0

I may need a bit more information to answer your question, but try these out:

The vast majority of elements in the periodic table are metals, meaning they have some degree of ductility and malleability, if you are being asked about physical properties.

The vast majority of elements in the periodic table are also solids at room temperature, if you are being asked about phase.

You might be interested in

CO2+2H2O=H3O^++HCO3^-

bekas [8.4K]

Answer:

Bronsted Lowry Theory

$CO_2$ is the acid

$H_2 O$ is the base

$H_3 O^+$ is the conjugate acid and

$HCO_3^-$ is the conjugate base

Explanation:

Bronsted Lowry Theory:

An acid is a substance that can donate one or more protons

A base is a substance which can accept one or more protons

Hydrogen atom which is neutral (No Charge) contains 1 positive proton, 1 negative electron and 0 neutral neutron.

Thus Hydrogen atom has no Charge and it is neutral.

When an hydrogen atom loses an electron, Hydrogen ion is formed, which will contain 1 positive proton and 0 negative electron and 0 neutral neutron.

Thus Hydrogen ion has a positive charge.

Hydrogen ion is also called as a proton since it has only 1 proton in it.

Hydrogen ion in water that is,

$H^++H_2O\Rightarrow H_3O^+$

$H_3O^+$ is called as Hydronium ion.

Acid loses H+ (proton) to form conjugate Base

Base gains H+ (proton) to form conjugate Acid

For example

Let us consider the example given in the question

$CO_2+2H_2 O>H_3 O^+ +HCO_3^-$ can be written as (removed 1 $H_2 O$ from both the sides )

$CO_2+H_2 O>H^++HCO_3^-$ or

$CO_2+H_2 O > H_2 CO_3$ reversing the equation

$H_2 CO_3+H_2 O>H_3 O^+ +HCO_3^-$

$H_2 CO_3$ is the acid which donates $H^+$ to form $HCO_3^-$

$H_2 O$ is the base which gains $H^+$ to form $H_3 O^+$

$HCO_3^-$ is the conjugate base and $H_3 O^+$ is the conjugate acid

$CO_2$ is the acid

$H_2 O$ is the base

$H_3 O^+$ is the conjugate acid and

$HCO_3^-$ is the conjugate base

(Answer)

5 0

2 years ago

Does brainy work with out Wi-Fi?

nikitadnepr [17]

Answer:

No it does not i have tried it once before and it would not load for me and it froze the whole page site. But it might be different for you...

Explanation:

6 0

2 years ago

Read 2 more answers

Question 12 of 25

NISA [10]

Answer:

B. Equal amounts of all gases have the same volume at the same

conditions

Explanation:

Amedo Avogadro found the relationship between volume of a gas and the number of molecules contained in the volume.

The law states that "equal volumes of all gases at the same temperature and pressure contains equal number of molecules or moles".

The law describes the behavior of gases when involve in chemical reactions. It enables one to change over at will in any statement about gases from volumes to molecules and vice versa.

So, the right option is B which implies that equal amounts of all gases have the same volume at the same conditions.

8 0

2 years ago

South carolinians feared that the hire terrace of 1828 would cause

ladessa [460]

They called it the Tariff of Abomination aka the Tariff of Evil because it really hurt the south. Any tariffs hurt the South with their agricultural business so I guess they believed it would lead to losing their jobs, etc..

5 0

2 years ago

How many multiple bonds in ch4

chubhunter [2.5K]

It has 8 bonding electrons

7 0

3 years ago