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lozanna [386]
3 years ago
14

Need help with question please .. -20 points

Chemistry
1 answer:
san4es73 [151]3 years ago
8 0

Answer:

B oklolol

[tex]\purple{\rule{45pt}{7pt}}\purple{\rule{45pt}{999999pt}}[tex]

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If the mass percentage composition of a compound is 72.1% Mn and 27.9% O, its empirical formula is
mojhsa [17]

Answer:

MnO- Manganese Oxide

Explanation:

Empirical formula: This is the formula that shows the ratio of elements

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How to determine Empirical formula

1. First arrange the symbols of the elements present in the compound

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2. Divide the percentage composition by the mass number.

3. Then divide through by the smallest number.

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a compound.

           

                                                                              Mn                         O    

                         

% composition                                                      72.1                      27.9    

                       

Divide by mass number                                       54.94                     16  

                                 

                                                                               1.31                      1.74    

                       

Divide by the smallest number                         1.31                      1.31                          

                                                                               1                    1.3

                                                 

The resulting ratio is 1:1

 

Hence the Empirical formula is MnO, Manganese oxide

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