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3 years ago

Write a linear factorization of the function. f(x) = x^4 + 64x^2

2 answers:

6 0

we are given with the function f(x) = x^4 + 64x^2 and is asked to factor the function. The greatest common factor of the terms is x^2 . hence taking out x^2 from the set, the result is x2 *(x2 + 64).(x2 + 64) is equal to (x+8)^2 - 16x. hence the linear factorization is x^2 * ( (x+8)^2 - 16x)

Gelneren [198K]3 years ago

3 0

Hello,

y=x^4+64x&
In IR, y=x^2(x^2+64).

In C, y=x²(x+8i)(x-8i)

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Find the 72nd term of the arithmetic sequence -27, -11, 5,

mixas84 [53]

Answer:

1109

Step-by-step explanation:

an = d (n - 1) + c

an = what you're looking for

n = term position

d = the common difference, in your case, 16

c = first term of the sequence, or -27

a₇₂ = 16(72 - 1) + -27 = 1109

5 0

3 years ago

If a = -8, b = -7, c = 6, then verify that (a+b) + c = a+ (b+c) tysm for de help ✨

NISA [10]

The given information is,

→ a = -8

→ b = -7

→ c = 6

Let's verify the problem,

→ (a+b) + c = a+ (b+c)

→ (-8 - 7) + 6 = -8 + (-7 + 6)

→ -15 + 6 = -8 - 1

→ -9 = -9

→ [ LHS = RHS ]

Hence, it is equal and verified.

5 0

2 years ago

What continues the pattern for 7 16 8 27 9

Butoxors [25]

38 10 49 11 60 12..
How
27 - 16 = 11
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6 0

3 years ago

PLEASE HELP WITH GRAPH LAST QUESTION I NEED

SVETLANKA909090 [29]

Answer:

$\sf g(x) = -1(x+3)^2 -2$

Explanation:

$\sf original \ graph: \ y=-x^{2}$

the graph is translated 3 units to the left and 2 units down.

vertex: (-3,-2) point: (-1,-6)

$\sf so \ new \ graph :$

$\sf y = a(x-h)^2 +k$

$\sf -6 = a(-1-(-3))^2 -2$

$\sf -6 = 4a -2$

$\sf 4a = -4$

$\sf a = -1$

$\sf equation:$

$\sf y = a(x-h)^2 +k$

$\sf y = -1(x+3)^2 -2$

6 0

2 years ago

Read 2 more answers

Find the work (in ft-lb) required to pump all the water out of a cylinder that has a circular base of radius 7 ft and height 200

Virty [35]

Answer:

work done is equal to 384279168 lb-ft

Step-by-step explanation:

The cylinder has a circular base of 7 ft.

The height of the cylinder is 200 ft

The weight density of water in the cylinder is 62.4 lb/ft^3

First, we find the volume of the water in the cylinder by finding the volume of this cylinder occupied by the water.

The volume of a cylinder is given as $\pi r^{2} h$

where, r is the radius,

and h is the height of the cylinder.

the volume of the cylinder = $3.142* 7^{2}*200$ = 30791.6 ft^3

Since the weight density of water is 62.4 lb/ft^3, then, the weight of the water within the cylinder will be...

weight of water = 62.4 x 30791.6 = 1921395.84 lb

We know that the whole weight of the water will have to be pumped out over the height of cylindrical container. Also, we know that the work that will be done in moving this weight of water over this height will be the product of the weight of water, and the height over which it is pumped. Therefore...

The work done in pumping the water out of the container will be

==> (weight of water) x (height of cylinder) = 1921395.84 x 200

==> work done is equal to 384279168 lb-ft

7 0

3 years ago