A polynomial function of least degree with integral coefficients that has the
given zeros 
Given
Given zeros are 3i, -1 and 0
complex zeros occurs in pairs. 3i is one of the zero
-3i is the other zero
So zeros are 3i, -3i, 0 and -1
Now we write the zeros in factor form
If 'a' is a zero then (x-a) is a factor
the factor form of given zeros

Now we multiply it to get the polynomial

polynomial function of least degree with integral coefficients that has the
given zeros 
Learn more : brainly.com/question/7619478
Can you please include a question please? Thank you
Y=mx+b
Mx is the rate of change
B is your starting point
Started with 1000, A
-200 is the rate of change, D
Answer:
a=35, b=14, c=5
Step-by-step explanation:
b+6=20, b+6-6=20-6, b=14
4c-6=14, 4c-6+6=14+6, 4c=20, 4c/4=20/4, c=5
a triangle's angles always add up to 180, 180-55-90(the square means right angle)=35
-4x^4 - 15x^2 + 1 - 19/x^2 is your answer
Hope I helped :)