We know angle x=y(vertically opposite angles)
Since 3 angles lie on a straight line,
y+60+70=180 (linear pair)
y+130=180
y=180-130
y=50 degrees
Answer:
Step-by-step explanation:
× 
6 x 6 = 36
4 + 3 = 7 (add exponents because its multiplication)
Answer:
About 108 times
Step-by-step explanation:
Given:
An average soccer player travels 7 miles during a game
A typical field is 104 meters long.
To find:
How many times did the average soccer play travel the length of the field?
Solution:
An average soccer player travels during the game = 7 miles
First convert 7 miles into meters, 1 mile = 1609.34 meter
7 mile = 1609.34 \times 7 = 11265.41 m
Length of field = 104 meters
To find number of times average soccer player travel the length of the field, we will divide an average soccer player travels during the game by Length of field
11265.41 m 
104 = 108.32
Therefore, about 108 times average soccer player travel the length of the field
The correct answer is B. -4<x<2.
This is because the domain is looking for the values of x that can be used in the function. In the picture below, you will notice that the leftmost point is at x = -4. This is as low as the x value goes. The rightmost point is at x = 2, which is as large as the x value gets. Therefore the domain is between those two numbers.
Y + 4x < 8
y < -4x + 8
2 points that satisfy this are (0,8) and (2,0)....and those happen to be ur x and y intercepts (where the line crosses the x and y axis)
graph...so go ahead and plot ur x and y intercepts (0,8) and (2,0).....ur slope is - 4.....so start at ur y int (0,8) and go down 4 spaces, and to the right 1...plot that point, then go down 4 spaces and to the right 1, then plot that point...keep doing this and u will have ur line...u should have crossed the x axis at (0,2)......ur line will be a dashed line since the problem has no equal sign.... the shading will go below the line because it is less then.
y - 3 > = 1/2x
y > = 1/2x + 3
2 points that satisfy this are : (0,3) and (-6,0)...ur x and y intercepts
graph : plot ur intercepts (0,3) and (-6,0)....u have a slope of 1/2...so start at ur x intercept (-6,0) and go up 1 space, and to the right 2 spaces, plot that point...then go up 1 and to the right 2, plot that point...keep doing this and u will cross the y axis at (0,3)....this line will be a solid line....the shading will go above the line.
