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aivan3 [116]
3 years ago
12

Find the side length. Round to the nearest tenth if necessary. 15

Mathematics
1 answer:
Rasek [7]3 years ago
8 0

Answer:

x = 39

Step-by-step explanation:

This is pythagoras

x = √36² + 15²

x = √1296 + 225

x = √1521

x = 39

Hopefully it helps you

Ask if u don't understand

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Graph the parabola.<br> y=-3x2 +6<br> PLEASE ANSWER quickly
beks73 [17]

Answer:

y = 12

Step-by-step explanation:

y = 3x2+6

   = 6+6

   = 12

y = 12

5 0
3 years ago
Trianas age is 5 years less than 3 times her brothers age. Trianas age is 11 minus her brothers age. How old is Triana?
erastova [34]

Answer: 7

HOPE THIS HELPS

8 0
3 years ago
The perimeter of the rectangle below is 74 units. Find the length of side RS
Alika [10]

Answer:

20 units

Step-by-step explanation:

The perimeter of a rectangle is

P = 2(l+w)

P = 2( 3x+2 + 4x)

Adding like terms

P = 2( 7x+2)

We know the perimeter is 74 units

74 = 2 ( 7x+2)

Divide by 2

74/2 = 2/2 (7x+2)

37 = 7x+2

Subtract 2 from each side

37-2 = 7x+2-2

35 = 7x

Divide by 7

35/7 = 7x/7

5 =x

We want to find the length RS = PQ = 4x

RS = 4x = 4*5 = 20

4 0
3 years ago
Read 2 more answers
Find the surface area of the prism
scoray [572]
Lets find the area of the 2 rectangles on the left and right side.
8*7 (2) = 112 (Both rectangles in total)
Now lets find the rectangles on the front and back.
13*7 (2) = 182
Now, the top and bottom ones.
13*8 (2) = 208
Add them all together.
112+182+208 = 502
The surface area is 502.
6 0
3 years ago
Read 2 more answers
How to find function definition area
insens350 [35]

Answer:Definition area"? Do you mean the "natural domain" of the function- the region in which the formula is defined? In order that a number have a square root that number must be non-zero.

Step-by-step explanation:Here, we must have x−1x≥0.

If x is positive, multiplying both sides by x we have x2−1=(x−1)(x+1)≥0. In order for that to be true, both x- 1 and x+ 1 must have the same sign: either x-1> 0 and x+ 1> 0 or x- 1< 0 and x+ 1< 0. The first pair of inequalities is true for x> 1 and the second for x< -1. Since "x is positive", we must have x> 1.

If x is negative, multiplying both sides by x we have x2−1=(x−1)(x+1)≥0. In order for that to be true, x- 1 and x+ 1 must have opposite signs: x+ 1> 0 and x- 1< 0 or x- 1<0 and x- 1> 0. The first pair is true for −1≤0≤1. The second pair are never both true. Since "x is negative" we must have −1≤x≤0.

Of course, we also cannot divide by 0 so x= 0 is not in the domain. The domain is the union of the two separate sets:{x|−1≤x<0}∪{x|x>1}.

Hope That Helps!

8 0
3 years ago
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