distance d = 5 km = 5 x 1000 m = 5000 m
time taken = 25 minute = 25 x 60 sec = 1500 sec
average velocity V = d/t
V = 5000/1500
V = 3.33 m/s towards east
According to Ohm's Law:

Where: V = Voltage
I = Current
R = Resistance
As you can see here, you can say that Current is directly proportional to Voltage and indirectly proportional to Resistance. This means that as the voltage increases, current increases and as the resistance increases, current decreases.
So in your scenario, if the voltage remains the same, but the resistance is doubled, that means that the current will be halved.
So the answer to your question is 2. the current will drop to half of its original value.
49 J is the total kinetic energy. If a bowling ball of mass 7.3 kg and radius 9.6 cm rolls without slipping down a lane at 3.1 m/s. Kinetic energy is the energy an bowling ball has because of its motion.
Given: m = 7.3 Kg ; r = 9.4 cm = 0.094 m ; v = 3.1 m
Now total kinetic energy in this case is given by KE = Kinetic energy due to rotation + Kinetic energy due to translation
i,e KE = 1/2*m*v2 + 1/2*I*ω2 where I is the moment of inertia of the bowling ball about it's center and ω is the angular velocity
Now for pure rotation (without slipping) v = rω
also for the ball (solid sphere) I = 2/5*m*r2
Hence our kinetic energy becomes
KE = 1/2*m*v2 + 1/5*m*v2 = 7/10*m*v2
so KE = 0.7*7.3*(3.1)2 = 49.10 J = 49 J
Learn more about kinetic energy here
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Answer:
a. V=11.84 m/s
b.x=0.052m
Explanation:
a).
Given
,
,
.







b).

No friction on the ball so:



Answer:
1.31×10^-9 C
Explanation:
Total charge = volume density × volume of sphere
Volume density = 6.1×10^-4 C/m^3
Volume of sphere = 4π/3×(outer radius - inner radius)^3 = 4×3.142/3 × (4.5 - 3.7)^3 = 4.189×0.8^3 = 2.145 cm^3 = 2.145×10^-6 m^3
Total charge = 6.1×10^-4 × 2.145×10^-6 = 1.31×10^-9 C