<u>Answer:</u>
Maximum height = 2040 m
<u>Explanation:</u>
We can solve the problem using kinematics.
Consider the vertical motion of the object and use the equation:
where:
• v = final velocity (0 m/s, because when the object is at max. height, it has no vertical velocity)
• u = initial velocity (400sin30° m/s ⇒ vertical component of 400 m/s at 30° to horizontal)
• a = acceleration (-9.81 m/s²; considering upward acceleration to be negative)
• s = displacement (? m; this represents the max. height of the object),
Substitute the values into the equation and solve for <em>s </em>:
⇒ 
⇒ 
(3 s.f.)
Answer:
Explanation:
By conservation of energy, speed of the ball going up = speed of ball coming down with the ball stops at the top.
Because the gravity acceleration is constant, by symmetry, half of total time, 6/2 = 3s, is for going up and the last 3s for coming down.
Consider the last 3s when the ball drops from top to bottom, the initial velocity = 0 and acceleration = 10m/s^2
distance traveled = initial velocity * time + 1/2 * acceleration * time^2
= 0*3 + 1/2*10*3^2
= 5*9
= 45m
So maximum height of the ball is 45m.
300 minuts
5 hours
1.2 killowatt
6 killowatt hour
6*0.15=0.9
$0.9
Answer:
Explanation:
Work is the product of force and distance.
We know the force to lift the rock was 50 Newtons. The work was 150 Joules.
- 1 Joule is equal to 1 Newton meters.
- We can convert the units to make the problem simpler later. The work is also 150 Newton meters.
Substitute the values into the formula.
We want to solve for distance, so we must isolate the variable. Divide both sides of the equation by 50 Newtons.
The Newtons will cancel out.
The rock was lifted <u>3 meters.</u>
Answer:
c. the rotation and revolution of the moon are the same as the earth
Explanation:
that we only see one side of the moon because the moon rotates around the Earth at the exact same speed as it rotates around its own axis, so that the same side of the moon is constantly facing the surface of the earth.
