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SCORPION-xisa [38]
3 years ago
7

Explain constellations and galaxies in detail.

Physics
1 answer:
DIA [1.3K]3 years ago
8 0

Constellations

<span>Is an area of the sky with defined boundaries, all stars and any other objects within that boundary are considered part of the constellation.There are 88 official constellations which are recognized by the International Astronomical Union.Some constellations are only visible in the northern hemisphere, while others are only visible in the southern hemisphere.<span>Constellations that are visible in both hemispheres may appear upside down in the southern hemisphere.

Galaxies
</span></span>

A galaxy is a <span>gravitationally bound system of stars, stellar remnants, interstellar gas, dust, and dark matter. The word galaxy is derived from the Greek galaxias (</span>γαλαξίας), literally "milky", a reference to the <span>Milky Way. Galaxies range in size from dwarfs<span> with just a few billion (109) stars to giants with one hundred </span>trillion<span> (1014) stars, each orbiting its galaxy's </span>center of mass. Galaxies are categorized according to their visual morphology as elliptical, spiral and irregular. Many galaxies are thought to have black holes at their active centers<span>. </span></span>

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A force Fof 40000 lbf is applied to rod AC the negative Y-direction. The rod is 1000 inches tall. A Force P of 25 lbf is applied
erastova [34]

Answer:

The answer is "effective stress at point B is 7382 ksi "

Explanation:

Calculating the value of Compressive Axial Stress:

\to \sigma y  =\frac{F}{A} = \frac{4 F}{( p d ^2 )} = \frac{(4 x ( - 40000 \ lbf))}{[ p \times (1 \ in)^2 ]} = - 50.9 \ ksi \\

Calculating Shear Transverse:

\to \frac{4v}{ 3 A} = \frac{4 (75 \ lbf + 25 \ lbf)}{ \frac{3 ( lni)^2}{4}}

        = \frac{4 (100 \ lbf)}{ \frac{3 ( lni)^2}{4}} \\\\ = \frac{400 \ lbf)}{ \frac{3 ( lni)^2}{4}} \\\\= 0.17 \ ksi

= R \times 200 \ in - P \times 100 \ in = 12500 \ lbf \times\  in

\to \sigma' =[ s y^2 +3( t \times y^2 + t yz^2 )] \times \frac{1}{2}\\\\

       = [ (-50.9)^2 +3((63.7)^2 +(0.17)^2 )] \times \frac{1}{2}\\\\=[2590.81+ 3(4057.69)+0.0289]\times \frac{1}{2}\\\\=[2590.81+12,173.07+0.0289] \times \frac{1}{2}\\\\=14763.9089\times \frac{1}{2}\\\\ = 7381.95445 \ ksi\\\\ = 7382 \ ksi

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Answer:

the string and metre rule

Explanation:

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