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3 years ago

How many moles of carbon are in 7.87x10^7 carbon molecules

Chemistry

1 answer:

Snezhnost [94]3 years ago

3 0

I not getting the value but I know the equation it is NO OF MOLECULES =AVAGADROS CONSTANT *NO OF MOLES

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Answer: Electrical energy is defined as an electric charge that lets work be accomplished. An example of electrical energy is power from a plug outlet. YourDictionary definition and usage example.

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3 years ago

How many moles are in 1.505x10^24 molecules of surcrose

algol [13]

Answer:

2.499 moles of sucrose

Explanation:

Divide by Avogadro's number

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3 years ago

MgSO3 spell out full name of compound

mamaluj [8]

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3 years ago

Read 2 more answers

A 34.57 mL sample of an unknown phosphoric acid solution is titrated with a 0.127 M sodium hydroxide solution. The equivalence p

Bas_tet [7]

<u>Answer:</u> The concentration of unknown phosphoric acid solution is 0.034 M

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_3PO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=3\\M_1=?M\\V_1=34.57mL\\n_2=1\\M_2=0.127M\\V_2=28.2mL$

Putting values in above equation, we get:

$3\times M_1\times 34.57=1\times 0.127\times 28.2\\\\M_1=\frac{1\times 0.127\times 28.2}{3\times 34.57}=0.034M$

Hence, the concentration of unknown phosphoric acid solution is 0.034 M

7 0

3 years ago

Two unknown molecular compounds were being studied. A solution containing 5.00 g of compound A in 100. g of water froze at a low

Shtirlitz [24]

Answer:

Compound B.

Explanation:

The freezing point depression is a colligative property. It depends on the number of particles (moles) present in the solution.

$\Delta T_{\text{f}} = K_{\text{f}} b$

where b is the molal concentration

$b = \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}\\\\n = \dfrac{\text{mass}}{\text{molar mass}} = \dfrac{m}{M}$

If m is constant (5 g), then

$n \propto \dfrac{1}{M}$

The compound with the greater molar mass has fewer moles and therefore fewer particles to depress the freezing point.

That must be Compound B, because Compound A has the lower freezing point.

7 0

3 years ago