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2 years ago

8. Determine the density of a cube that has a mass of 40.5g and a volume of 9cm3 .

Physics

1 answer:

Alika [10]2 years ago

4 0

Answer:

d = 2.70 g/mL

Explanation:

search the next one up on go ogle it will give you an answer i promise

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How many millimeters are 120 meters ? Help ! Please <3

blsea [12.9K]

Answer:

120,000

Explanation:

Millimeters to meters calculation-

Multiply by 1,000.

120 x 1,000 = 120,000.

This is the correct answer and formula.

Hope this helps!

8 0

3 years ago

Read 2 more answers

A particle in uniform circular motion requires a net force acting in what direction?

mel-nik [20]

The net force will point towards the acceleration of the object, as supported by Newton's second law.

6 0

4 years ago

70-kg man standing on a scale in an elevator notes that as the elevator rises, the scale reads 844 N. What is the acceleration o

mario62 [17]

Answer : The acceleration of the elevator is, $2.25m/s^2$

Explanation :

Formula used to calculate the acceleration of the elevator is:

$F=mg+ma\\\\ma=F-mg\\\\a=\frac{F-mg}{m}$

where,

F = force = 844 M

m = mass of man = 70 kg

g = acceleration due to gravity = $9.8m/s^2$

a = acceleration of the elevator = ?

Now put all the given values in the above formula, we get:

$a=\frac{F-mg}{m}$

$a=\frac{844N-(70kg\times 9.8m/s^2)}{70kg}$

$a=2.25m/s^2$

Thus, the acceleration of the elevator is, $2.25m/s^2$

4 0

3 years ago

A jet plane lands with a speed of 87 m/s and can accelerate at a maximum rate of −4.10 m/s2 as it comes to rest. (a) From the in

garri49 [273]

Answer:

21.22s

Explanation:

initial velocity u=87m/s

acceleration a=-4.10 m/s²

velocity v=0

time t=?

From Newton's first law of motion

V=u+at

0=87-4.10t

-87=-4.1t

t= -87/-4.1

t= 21.22 s

7 0

3 years ago

When skydiver nellie opens her parachute, the air drag pushing the chute upward is stronger than earth's force of gravity pullin

Reil [10]

No, the skydiver does not start moving upward. Yes, initially the air drag is stronger than the weight, and so there is a net force pushing upward, and the result of this force (because of F=ma) is a deceleration of the skydiver (because the force goes against the direction of motion). However, the air drag is proportional to $v^2$ , the square of the velocity. Thus, as the velocity of the skydiver decreases, so does the air drag, and eventually the air drag becomes smaller than the weight. So the skydiver continues his motion towards the ground.

5 0

3 years ago