Answer:
Maximum height reached by the ball is 32 meters.
Explanation:
It is given that,
If a baseball is project upwards from the ground level with an initial velocity of 32 feet per second, then it's height is a function of time. The equation is given as :
...........(1)
t is the time taken
s is the height attained as a function of time.
Maximum height achieved can be calculated as :
-16 t + 32 = 0
t = 2 seconds
Put the value of t in equation (1) as :
s = 32 meters
So, the maximum height reached by the ball is 32 meters. Hence, this is the required solution.
Answer: FR=2.330kN
Explanation:
Write down x and y components.
Fx= FSin30°
Fy= FCos30°
Choose the forces acting up and right as positive.
∑(FR) =∑(Fx )
(FR) x= 5-Fsin30°= 5-0.5F
(FR) y= Fcos30°-4= 0.8660-F
Use Pythagoras theorem
F2R= √F2-11.93F+41
Differentiate both sides
2FRdFR/dF= 2F- 11.93
Set dFR/dF to 0
2F= 11.93
F= 5.964kN
Substitute value back into FR
FR= √F2(F square) - 11.93F + 41
FR=√(5.964)(5.964)-11.93(5.964)+41
FR= 2.330kN
The minimum force is 2.330kN
The correct answer to your question and how to solve it is
The relation between wavelength (λ)and the frequency of electromagnetic oscillation (f) is described by the following expression: λ=c/f, where c–is the speed of light in vacuum = 3*10^8 m/s
Derive f from above: f = c/λ.How to Calculate: λ=890nm = 890*10^-9m = 8.9*10^-7m
f =3*10^8m/s Divided by 8.9*10^-7m = 0.34*10^15 s-1=3.4*10^14 s-1
So your Answer is: The frequency of radiation of wavelength 890 nm is 3.4*10^14s-1
Answer:
The acceleration of car 2 is four times of the acceleration of car 1.
Explanation:
The centripetal acceleration of the object is possessed when it moves in a circular path. It is given by :
In this case, two race cars are driving at constant speeds around a circular track. Both cars are the same distance away from the center of the track, but car 2 is driving twice as fast as car 1.
So,
1 and 2 represent car 1 and car 2 respectively.
So,
So, the acceleration of car 2 is four times of the acceleration of car 1.
We have that the Throw has changed in distance the ball has traveled and the Force applied in trowing the ball and Possibly the time of travel
From the Question we are told that
You toss a ball to someone one meter away
You toss it to someone four meters away
Generally
When you toss toss a ball to someone one meter away and You toss it to someone four meters away the are things that have changed
Therefore
The Throw has changed in distance the ball has traveled and the Force applied in trowing the ball and Possibly the time of travel
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