Answer:
For bbff we have only 6.3% probability
Step-by-step explanation:
If the parents are heterozygous for both traits, them they are represented by:
BbFf × BbFf
Parent 1: BbFf
Parent 2: BbFf
We have to find the percentage of occurence of bb × ff, which is a child that has blue eyes and no freckles, with no dominant factor.
By distributing the possibilities in a Punnett square, <em>vide</em> picture. We have the following possibilities:
Genotype Count Percent
bBfF 4 25
BBfF 2 12.5
bBFF 2 12.5
bBff 2 12.5
bbfF 2 12.5
BBFF 1 6.3
BBff 1 6.3
bbFF 1 6.3
bbff 1 6.3
For bbff we have only 6.3% probability
Answer:

Step-by-step explanation:
<u>Given:</u>

<u>Use the Power Rule Law:</u>

<u>Use the Quotient Rule Law:</u>

<u>Use the Product Rule Law:</u>

<u>Simplify:</u>






Answer:
?????????????????
Step-by-step explanation:
????????
You take out the biggest factor of 9 and 36 which is 9c^2. The factors both have the c variable in common so you take the least exponent and put it with the gcf.
9c^2(c^2+4)
3.360e17
Explanation:
I rounded to the nearest thousandth.
Hope this helps!