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mafiozo [28]
3 years ago
5

Whats the difference between relative dating and absolute dating

Physics
2 answers:
valentina_108 [34]3 years ago
5 0
Relative Dating- Scientists compare the fossil(s) to its surroundings to get a close answer to the age.
Absolute Dating - Use a specified Chronology in archeology and geology, this helps to decide the exact age of the fossil(s). 
Absolute Dating has a greater accuracy than that of Relative Dating.
djyliett [7]3 years ago
3 0
Relative dating<span> and absolute </span>dating<span> are used to determine age of fossils and geologic features, but with </span>different<span> methods. </span>Relative dating<span> uses observation of location within rock layers, while absolute </span>dating<span> uses data from the decay of radioactive substances within an object.</span>
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vazorg [7]

The velocity of the boat after the package is thrown is 0.36 m/s.

<h3>Final velocity of the boat</h3>

Apply the principle of conservation of linear momentum;

Pi = Pf

where;

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  • Pf is final momentum

v(74 + 135) = 15 x 5

v(209) = 75

v = 75/209

v = 0.36 m/s

Thus, the velocity of the boat after the package is thrown is 0.36 m/s.

Learn more about velocity here: brainly.com/question/6504879

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Answer:

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Explanation:

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An object with a mass M = 250 g is at rest on a plane that makes an angle θ = 30 o above the horizontal. The coefficient of kine
liubo4ka [24]

Answer:

v = 79.2 m/s

Solution:

As per the question:

Mass of the object, m = 250 g = 0.250 kg

Angle, \theta = 30^{\circ}

Coefficient of kinetic friction, \mu_{k} = 0.100

Mass attached to the string, m = 0.200 kg

Distance, d = 30 cm = 0.03 m

Now,

The tension in the string is given by:

Mgsin\theta + \mu_{k}Mgcos\theta + Ma = T        (1)

Also

T = m(g + a)

Thus eqn (1) can be written as:

Mgsin\theta + \mu_{k}Mgcos\theta + Ma = m(g - a)

Mgsin\theta + \mu_{k}Mgcos\theta + Ma = mg + ma

mg - Mgsin\theta - \mu_{k}Mgcos\theta = (M - m)a

a = \frac{0.2\times 9.8 - 0.250\times 9.8\times sin30^{\circ} - 0.1\times 0.250\times 9.8\times cos30^{\circ}}{0.250 - 0.200}

a = 10.45\ m/s^{2}

Now, the speed is given by the third eqn of motion with initial velocity being zero:

v^{2} = u^{2} + 2ad

where

u = initial velocity = 0

Thus

v = \sqrt{2ad}

v = \sqrt{2\times 10.45\times 0.03} = 0.792\ m/s

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3 years ago
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lina2011 [118]

Answer:

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14. Which is the relationship between photon energy and frequency?
yawa3891 [41]

Answer:

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Explanation:

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