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Mila [183]
3 years ago
8

A student is sitting at rest in a chair. How does the force that the student exerts

Physics
1 answer:
jonny [76]3 years ago
3 0

Answer:

the same magnitude but the opposite direction

Explanation:

Newton's third law of motion states that there is always an equal and opposite reaction to every action. This means that the amount of force exerted upon an object is equal to the amount of force the object exerts but in an opposite direction.

This is the case in this scenario where a student sits at rest in a chair. The student is supplying the action force being exerted on the chair. According to the third law of Newton, the chair will exert the same size of force back in the student but in an opposite direction.

Hence, the force the chair exerts on the students compare with that of the student in the sense that they are the same magnitude (size) but the opposite directions.

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Answer:

D. 90

Explanation:

because even if there is a shadow of doubt the person should not be persecuted as it could lead to false imprisonment

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3 years ago
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MrRa [10]
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(a) As you ride on a Ferris wheel, your apparent weight is different at the top and at the bottom. Explain. (b) Calculate your a
otez555 [7]

Answer:

a. The component of the net force which make up the apparent weight are added to each other at the bottom and subtracted (the centripetal force from the weight) at the top)

b. Apparent weight at the top is approximately 519.06 N

Apparent weight at the bottom is approximately 558.94 N

Explanation:

a. The apparent weight at the top is different from the apparent weight at the bottom of a moving Ferris wheel because of the opposite direction in which the centripetal force acts at the top and the bottom, which are upwards and downwards respectively, while the weight acts downwards constantly

b. The given parameters are

The radius of the Ferris wheel, r = 7.2 m

The period for one complete revolution, t = 28 seconds

The angle covered in one revolution, θ = 2·π radian

The mass of the person riding on the Ferris wheel, the passenger  = 55 kg

Therefore, we have;

The angular speed, ω = Δθ/Δt = 2·π/(28)

From which we have;

Centripetal force, F_c = m × ω² × r

Substituting the known values, we have F_c = 55 kg × (2·π/(28 s))² × 7.2 m ≈ 19.94 N

The centripetal force, F_c = 19.94 N always acting outward from the center

Weight = Mass × Acceleration due to gravity

The weight of the passenger = 55 kg × 9.8 m/s² = 539 N

The weight of the passenger = 539 N always acting downwards

At the top of the Ferris wheel the the centripetal force is acting upwards and the weight is acting downwards

Therefore;

The net force, which is the apparent weight of the passenger at the top F_{NET_{Top}} = 539 N - 19.94 N ≈ 519.06 N

Apparent weight at the top ≈ 519.06 N

At the bottom of the Ferris wheel the weight is acting downwards and the centripetal force is also acting downwards

Therefore;

The net force at the bottom, which is the apparent weight of the passenger at the bottom F_{NET_{bottom}} = 539 N + 19.94 N ≈ 558.94 N

Apparent weight at the bottom ≈ 558.94 N.

5 0
3 years ago
Gaseous helium is in thermal equilibrium with liquid helium at 6.4 K. The mass of a helium atom is 6.65 × 10−27 kg and Boltzmann
chubhunter [2.5K]

Answer:

162.78 m/s is the most probable speed of a helium atom.

Explanation:

The most probable speed:

v_{mp}=\sqrt{\frac{2K_bT}{m}}

K_b= Boltzmann’s constant =1.38066\times 10^{-23} J/K

T = temperature of the gas

m = mass of the gas particle.

Given, m = 6.65\times 10^{-27} kg

T = 6.4 K

Substituting all the given values :

v_{mp}=\sqrt{\frac{2\times 1.38066\times 10^{-23} J/K\times 6.4 K}{6.65\times 10^{-27} kg}}

v_{mp}=162.78 m/s

162.78 m/s is the most probable speed of a helium atom.

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A 388 Hz tuning fork is resonating in a closed tube on a warm day when the speed of sound is 346 m/s. What is the length of the
Marizza181 [45]

Answer:

A

Explanation:

because u are subtracting if this is from flvs that is what i did and it was right

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