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3 years ago

A student is sitting at rest in a chair. How does the force that the student exerts

Physics

1 answer:

jonny [76]3 years ago

3 0

Answer:

the same magnitude but the opposite direction

Explanation:

Newton's third law of motion states that there is always an equal and opposite reaction to every action. This means that the amount of force exerted upon an object is equal to the amount of force the object exerts but in an opposite direction.

This is the case in this scenario where a student sits at rest in a chair. The student is supplying the action force being exerted on the chair. According to the third law of Newton, the chair will exert the same size of force back in the student but in an opposite direction.

Hence, the force the chair exerts on the students compare with that of the student in the sense that they are the same magnitude (size) but the opposite directions.

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Imagine a universe in which, like in ours, there are two kinds of charges (positive and negative), with the like charges repelli

GuDViN [60]

Answer:

the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude

Explanation:

In this hypothetical system the electric force is of type

F = $k' \frac{q_1 q_2 }{r^2}$

in this case the force decays to zero much faster,

if we call Fo the force of Coulomb's law

F₀ = $k \frac{q_1 q_2 }{r^2}$

assuming the constant k is the same

the relationship between the two forces is

F / F₀ = 1 / r

F = F₀ / r

when analyzing this expression the force decays much faster to zero.

In an electric conductor, charges of the same sign may not feel any repulsive force from other charges that are at a medium distance, so there is a probability that some charges are distributed in the volume of the material, this does not happen with coulomb's law

Consequently, the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude

5 0

3 years ago

What happens when a roller coaster car moves down from the top of a hill?

VLD [36.1K]

When the roller coaster moves down from the top of the hill, all of its stored potential energy is converted into kinetic energy to move it and when it goes back up the hill it turns kinetic into potential.

3 0

3 years ago

Read 2 more answers

Quiz Review Problems

zlopas [31]

The momentum of a neutron p = 586.25 kg m / s.

<u>Explanation:</u>

The product of mass and the velocity gives the momentum of an object and it is a vector quantity. It is denoted by the letter p. The unit of momentum is kilogram meter per second (or) kg m / s.

Given mass m = 1.675 $\times$ 10, velocity v = 3.500 $\times$ 10

Momentum, p = mv

where m represents the mass,

v represents the velocity.

momentum p = (1.675 $\times$ 10) $\times$ (3.500 $\times$ 10)

momentum p = 586.25 kg m / s.

5 0

3 years ago

a 0.0780 kg lemming runs off a 5.36 m high cliff at 4.84 m/s. what is its kinetic energy when it's 2.00 m above the ground

Blababa [14]

Answer:

KE_2 = 3.48J

Explanation:

Conservation of Energy

E_1 = E_2

PE_1+KE_1 = PE_2+KE_2

m*g*h+(1/2)m*v² = m*g*h+(1/2)m*v²

(0.0780kg)*(9.81m/s²)*(5.36m)+(.5)*(0.0780kg)*(4.84m/s)² = (0.0780kg)*(9.81m/s²)*(2m)+KE_2

4.10J+0.914J = 1.53J + KE_2

5.01J = 1.53J + KE_2

KE_2 = 3.48J

3 0

3 years ago

Am radio signals have frequencies between 550 khz and 1600 khz (kilohertz) and travel with a speed of 3.00 ✕ 108 m/s. what are t

Allisa [31]

The minimum frequency is
$f_1 = 550 kHz = 5.50 \cdot 10^5 Hz$
while the maximum frequency is
$f_2 = 1600 kHz = 1.6 \cdot 10^6 Hz$
Using the relationship between frequency f of a wave, wavelength $\lambda$ and the speed of the wave v, we can find what wavelength these frequencies correspond to:
$\lambda_1 = \frac{v}{f_1}= \frac{3 \cdot 10^8 m/s}{5.5 \cdot 10^5 Hz}=545 m$
$\lambda_2 = \frac{v}{f_2}= \frac{3 \cdot 10^8 m/s}{1.6 \cdot 10^6 Hz}=188 m$

So, the wavelengths of the radio waves of the problem are within the range 188-545 m.

5 0

3 years ago