Answer:
(A) Work done will be 87.992 KJ
(B) Work done will be 167.4 KJ
Explanation:
We have given mass of methane m = 4.5 gram = 0.0045 kg
Volume occupies ![V_1=12.7dm^3=12.7liters](https://tex.z-dn.net/?f=V_1%3D12.7dm%5E3%3D12.7liters)
And volume is increased by
so ![V_2=12.7+3.3=16liters](https://tex.z-dn.net/?f=V_2%3D12.7%2B3.3%3D16liters)
Temperature T = 310 K
Pressure is given as 200 Torr = 26664.5 Pa
(a) At constant pressure work done is given by
![W=P(V_2-V_1)=26664.5\times (16-12.7)=87992.85J=87.992kj](https://tex.z-dn.net/?f=W%3DP%28V_2-V_1%29%3D26664.5%5Ctimes%20%2816-12.7%29%3D87992.85J%3D87.992kj)
(b) At reversible process work done is given by ![W=nRTln\frac{V_2}{V_1}](https://tex.z-dn.net/?f=W%3DnRTln%5Cfrac%7BV_2%7D%7BV_1%7D)
We have given mass = 4.5 gram
Molar mass of methane = 16
So number of moles ![n=\frac{mass\ in\ gram}{mol;ar\ mass}=\frac{4.5}{16}=0.28125](https://tex.z-dn.net/?f=n%3D%5Cfrac%7Bmass%5C%20in%5C%20gram%7D%7Bmol%3Bar%5C%20mass%7D%3D%5Cfrac%7B4.5%7D%7B16%7D%3D0.28125)
So work done ![W=0.28125\times 8.314\times 310ln\frac{16}{12.7}=167.4J](https://tex.z-dn.net/?f=W%3D0.28125%5Ctimes%208.314%5Ctimes%20310ln%5Cfrac%7B16%7D%7B12.7%7D%3D167.4J)
E, there is no state of matter that has no particle motion, however a solid's particles are only vibrating.
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The balloon explodes, because the pressure builds up inside and the air want to expand. Letter a)
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When someone stands against a locker and is does not moving at all, then there will be no displacement and since displacement = 0
Work done also becomes equal to zero.
Work done is usually defined as change in energy. Since the work done is zero there has been no energy used.