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Anvisha [2.4K]
3 years ago
15

At 10:00 a.m. two boys start out on their bikes to meet each other from towns located 68 miles apart. At 1:00 p.m. they meet. If

one boy traveled 3 miles per hour faster than the other, what was the rate of speed of each boy?
Mathematics
1 answer:
algol [13]3 years ago
4 0
A = speed of one boy 
<span>a + 3 = speed of 2nd boy </span>

<span>d = speed X time ... time is 3 hrs </span>

<span>68 = 3a + 3(a + 3) </span>
<span>6a = 59 </span>
<span>a = 59/6 = 9 5/6 miles per hour </span>
<span>a + 3 = 12 5/6 miles per hou</span>
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