At 10:00 a.m. two boys start out on their bikes to meet each other from towns located 68 miles apart. At 1:00 p.m. they meet. If
one boy traveled 3 miles per hour faster than the other, what was the rate of speed of each boy?
1 answer:
A = speed of one boy
<span>a + 3 = speed of 2nd boy </span>
<span>d = speed X time ... time is 3 hrs </span>
<span>68 = 3a + 3(a + 3) </span>
<span>6a = 59 </span>
<span>a = 59/6 = 9 5/6 miles per hour </span>
<span>a + 3 = 12 5/6 miles per hou</span>
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The answer is 16 because 16 plus 3 equals 19
The answer is B.
172.0 in.²
Answer:
y = -3x - 2
Step-by-step explanation:
slope (m) = (-8 - -5) / (2 - 1) ... difference of y/difference of x
m = -3
y = mx + b
y = -3x + b
for (3,-11) b = y + 3x = -11 + 3x3 = -2
equation: y = -3x - 2
The initial value is 3 (when x=0), and the multiplier is 2, when x=2. The equation can be written as
.. y = 3*(2^(x/2))
The answer to 6 2/3 divide by 9 2/3 should equal to 20/29.
