Question

At 10:00 a.m. two boys start out on their bikes to meet each other from towns located 68 miles apart. At 1:00 p.m. they meet. If one boy traveled 3 miles per hour faster than the other, what was the rate of speed of each boy?

Answer 1

A = speed of one boy 
a + 3 = speed of 2nd boy 

d = speed X time ... time is 3 hrs 

68 = 3a + 3(a + 3) 
6a = 59 
a = 59/6 = 9 5/6 miles per hour 
a + 3 = 12 5/6 miles per hou