Answer:
The time taken the same amount of ammonia to effuse through the same barrier under the same conditions is 2.76 minutes.
Explanation:
Let the volume of the helium gas be = V
Time taken by the helium gas = t = 1.34 min
Effusion rate of helium gas = 
If V volume of ammonia effuse through same porous barrier the effusion rate of ammonia gas will be given as:

Using Graham's Law.
This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

Molar mass of helium gas = M = 4 g/mol
Molar mass of ammonia gas = M' = 17 g/mol



The time taken the same amount of ammonia to effuse through the same barrier under the same conditions is 2.76 minutes.
Answer: Option (d) is the correct answer.
Explanation:
When a hydrogen atom comes in contact with an electronegative atom then it results in the formation of a chemical bond.
More is the electronegativity of combining atom, more stronger will be the bond with hydrogen atom. As a result, the compound formed will not easily give up hydrogen atom upon dissociation.
Whereas less is the electronegativity of atom combining with hydrogen atom, easily it will donate the hydrogen atom upon dissociation.
Since, out of the given option sulfur (S) atom has low electronegativity as compared to oxygen and nitrogen atom.
Hence,
will easily donate hydrogen atom.
Thus, we can conclude that
molecule would be the best hydrogen bond donor.
Answer:
Number 1 is false
Explanation:
1.- Charged molecules are insoluble in water. The statement is false, charged molecules are soluble in water and this is the main characteristic of charged molecules.
2.- Hydrophobic molecules tend to be nonpolar and hydrophilic molecules tend to be polar. This is true, hydrophobic molecules are non polar and hydrophilic molecules are polar.
3.- Gasoline has partial positive and negative charges which allows it to dissolve in water. This is true, gasoline is soluble in water.
4.- NH3 dissolves in water because its molecules form hydrogen bonds with water. This is true, NH3 interact with water because they can form hydrogen bonds.
5.- Hydrophobic molecules prefer to interact with each other in an aqueous solution. Absolutely true, hydrophobic molecules interact among them and they isolate from the environment.
i) Be has a fully filled 2s level.
ii) This is because chlorine is larger than fluorine.
iii) Fluorine needs only one electron to attain the octet configuration.
Electron affinity is the ability of an electron to accept gaseous electrons to yield gaseous ions with a negative charge.
Electron affinity depends on the size of an atom. Larger atoms have a higher electron affinity because they are better able to accept electrons.
The drop between Li and Be is because the 2s orbital in Be is already fully filled while Li has incompletely filled 2s level. electrons do not easily go into the higher energy 2p level.
The higher peak of chlorine is because chlorine is larger than fluorine hence the electron affinity of fluorine is less than that of chlorine. The smaller the ion the lesser the electron affinity.
Fluorine has the highest electron affinity in period 2 because it needs only one electron to attain the octet structure.
brainly.com/question/11755303
Answer:
See detailed explanation.
Explanation:
Hello!
In this case, for the reaction:

It is known that the equilibrium constant tends to be greater than 1; therefore, it is a reaction that tends to go rightwards towards the formation of hydrogen iodide.
a) Here, since the reaction tends to form the product, it is clear that the initial concentration of iodine and hydrogen will decrease as the reaction reaches equilibrium in order to increase the concentration of hydrogen iodide.
b) Yes, it stops at the point in which the following expression:
![\frac{[HI]^2}{[I_2][H_2]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BHI%5D%5E2%7D%7B%5BI_2%5D%5BH_2%5D%7D)
Equals the equilibrium constant.
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