Answer:
It contains 0.105 mole cu
Explanation:
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Answer:
0.41 moles.
Explanation:
Given that:
Mass of helium = 4.00 g
Initial Volume = 24.4 L
initial Temperature = 25.0 °C =( 25 + 273) = 298 K
initial Pressure = 1.00 atm
The volume was reduced to :
i.e
final volume of the helium - 10.4 L
Change in ΔV = 24.4 - 10.4 = 10.0 L
Temperature and pressure remains constant.
The new quantity of gas can be calculated by using the ideal gas equation.
PV = nRT
n =
n =
n = 0.4089 moles
n = 0.41 moles.
The metal is aluminium
<u>Explanation:</u>
Given:
Heat, q = 4680 J
Mass, m = 100g = 0.1kg
ΔT = 52°C
sample = ?
We know:
q = mcΔT
On substituting the value we get:
Thus, the metal is aluminium which has a specific heat capacity of 900 J/kg°C