It’s water vapor, does this help?
The energy released from 1 gram of uranium is more than 1 million times greater than the energy released from 3 grams of coal is True.
<u>Explanation:</u>
Nuclear Fission is the process in which splitting of a nucleus takes place that releases free neutrons and lighter nuclei. The fission of heavy elements like "Uranium is highly exothermic" and releases "200 million eV" compared to the energy that is released by burning coal which gives a few eV.
In the given example, it is obvious that the energy released from 1 gram of uranium is more than that of the energy released from 3 grams of coal because the amount of energy released during nuclear fission is millions of times more efficient per mass than that of coal considering only 
part of the original nuclei is converted to energy.
<h3>Answer:</h3>
Rb = + 1
S = + 4
O = - 2
<h3>Explanation:</h3>
Oxidation states of the elements were calculated keeping in mind the basic rules of assigning oxidation states which included assignment of +1 charge to first group elements i.e. Rubidium (Rb) and assignment of -2 charge to Oxygen atom. Then the oxidation state of Sulfur was calculated as follow,
Rb₂ + S + O₃ = 0
Above zero (0) means that the overall molecule is neutral.
Putting values of Rb and O,
(+1)₂ + S + (-2)₃ = 0
(+2) + S + (-6) = 0
+2 + S - 6 = 0
S - 6 = -2
S = -2 + 6
S = + 4
True sis is true period...
Two Half Cell reactions are as follow,
3e⁻ + Al⁺³ → Al (Reduction Reaction)
Mg → Mg⁺² + 2e⁻ (Oxidation Reaction)
In order to balance the number of electrons, multiply reduction reaction by 2 and oxidation reaction by 3.
So,
6e⁻ + 2 Al⁺³ → 2 Al
3 Mg → 3 Mg⁺² + 6e⁻ (e⁻ cancelled)
_______________________
2 Al⁺³ + 3 Mg → 2 Al + 3 Mg⁺²
Result:
At Anode Magnesium metal is Oxidized and At Cathode Aluminium Ions are reduced.
