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Harlamova29_29 [7]
3 years ago
8

x - 2 \div x(x {}^{2} - 4)" alt=" - x - 2 \div x(x {}^{2} - 4)" align="absmiddle" class="latex-formula">






​
Mathematics
1 answer:
saw5 [17]3 years ago
8 0

Answer:

Step-by-step explanation:

Hello,

First of all we will take any real number x different from 0, -2, +2 as dividing by 0 is not allowed and then we can write

\dfrac{( - x - 2)}{x(x^2 - 4)}=-\dfrac{x+2}{x(x-2)(x+2)}=\large \boxed{ -\dfrac{1}{x(x-2)}}

because we know that

x^2-4=x^2-2^2=(x-2)(x+2)

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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Answer:

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All of it put together (same text as above):

Decimals are a part of a whole just like fractions are a part of a whole. Therefore, a positive decimal is ALWAYS greater than a negative decimal. When you have two negative decimals, the one closer to zero is always greater. The farther a negative decimal is from zero, the smaller its value.

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