The change in the standard Gibbs free energy (ΔGº) for the dissociation of nitrous acid (HNO2) at 298 K is 19.09 kJ. If the pH of the solution after equilibrium is reached is 1.30 and the NO2 – concentration at equilibrium is 0.00060 M. What is the equilibrium concentration of HNO2? Hint: Use pH to determine the equilibrium concentration of H+ .
HNO2(aq) H + (aq) + NO2 – (aq)
Explanation:
When OH- (as in potassium hydroxide) is added, it reacts with the acid (HOCl) to reduce the amount of HOCl and increase the concentration of sodium hypochlorite.
Potassium hydroxide will react with the hypochlorous acid to produce hypochlorite ions. In the process, some of the weak acid will be consumed, along with the added strong base.
This occurs as follows:
HClO(aq) + KOH(aq) → KClO(aq) + H2O(l)
since water is formed, this maintains the pH. Thus ...
A. The number of moles of HClO will decrease. - TRUE
B. The number of moles of ClO- will increase. - TRUE
C. The equilibrium concentration of H3O+ will remain the same. - TRUE
D. The pH will decrease. - FALSE
E. The ratio of [HClO] / [ClO-] will decrease. -TRUE. It will decrease as HClO goes down and ClO- goes up.
Answer: The name of given molecule is
3-Methylpent-2-ene.
Explanation: First of all a carbon chain of five carbons was drawn. Then a double bond was made between carbon 3 and 4 (starting from left). A methyl group was drawn at middle carbon which is at position 3.
Molecule sketched was named as,
1) A longest chain containing double bond was selected and numbering was started from the end closest to double bond. Hence,
2-Pentene or
Pent-2-ene2) The position of substituent was specified before the parent name, Hence,
3-Methyl-2-Pentene or
3-Methylpent-2-ene