If the water molecule was linear instead of bent the water would no longer produce hydrogen bonds.
<u>Explanation:</u>
- Yes, If the water molecule was linear instead of bent the water would no longer produce hydrogen bonds.
- The water would no longer generate hydrogen bonds.
- It will lose its polar features and nearly all of its features will change such as boiling point, water tension and solubility.
- It would be more like to gas, rather than liquid.
- If the water was in the linear, the water would have all the features and it would produce the hydrogen bonds.
Answer:
Under high temperatures and low pressure, gases behave the most ideal.
Explanation:
Low pressure reduces the effect of the finite size of real particles by increasing the volume around each particle, and a high temperature gives enough kinetic energy to the particles to better overcome the attractions that exist between real particles. (Prevents sticking.)
In summary, real gases behave more like ideal gases when they are far away from a phase boundary, (condensation or freezing).
Answer:
nor its just
Explanation:
9 i need answer to be longer so im typing this out
Answer:
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" 2 Li + Br2<span> ----> 2 LiBr " .
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Answer:
In 23.49 minutes the concentration of A to be 66.8% of the initial concentration.
Explanation:
The equation used to calculate the constant for first order kinetics:
.....(1)
Rate law expression for first order kinetics is given by the equation:
![t=\frac{2.303}{k}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B2.303%7D%7Bk%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
......(2)
where,
k = rate constant
=Half life of the reaction = 
t = time taken for decay process = ?
![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
= initial amount of the reactant = 0.163 M
[A] = amount left after time t = 66.8% of
[A]=
t = 1,409.19 s
1 minute = 60 sec
In 23.49 minutes the concentration of A to be 66.8% of the initial concentration.
