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polet [3.4K]
3 years ago
9

Label the following as a pure substance or a mixture.

Chemistry
2 answers:
Zigmanuir [339]3 years ago
6 0

Answer: a mixture

Explanation:

Snezhnost [94]3 years ago
5 0

Answer:

b

Explanation:

can you help ,meeeeee

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An element has an atomic number of 10. The number of protons and electrons in a neutral atom of the element are ____.
Gekata [30.6K]
10 protons and 10 electrons
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PLEASE HURRY Which element has the largest atomic radius?<br><br> As<br> N<br> P<br> Sb
notsponge [240]
Sb has the largest atomic radius by 206
5 0
4 years ago
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When 25.0 mL of a solution of 1.4 x 10-3 M silver nitrate is mixed with 60.0 mL of a solution of 7.5 x 10-4 M sodium chloride a)
LUCKY_DIMON [66]
Step  one write  the  equation  for  dissociation  of  AgNO3  and  NaCl

that  is   AgNO3-------> Ag+   + NO3-

            NaCl-------->   Na+   +  Cl-
then  find  the  number  of  moles  of  each  compound
that  is  for   AgNO3  = ( 1.4 x10^-3 ) x  25/1000=  3.5  x10^-5  moles
                     Nacl=  (7.5  x10^-4)x 60/1000=  4.5  x10^-5  moles

from   mole  ratio  the  moles  of    Ag+=  3.5  x10^-5 moles  and  that  of  Cl-= 4.5  x10^-4 moles

  then find  the  total    volume  of  the  mixture
that  is  25ml  +  60 Ml  =85ml  =  0.085 liters

The  Ksp  of  Agcl =  (Ag+) (cl-),    let  the  concentration  of  Ag+ be  represented   by  x  and   also  the  concentration  be  represented by  x

ksp (1.8 x10^-10)  is  therefore=  x^2

find  the  square  root   x=1.342   x10^-5

Ag+ in  final  mixture  is =  moles  of  Ag+/total  volume - x
that is  {(3.5  x10^-5)/0.085}  -  1.342  x10^-5=3.98x10^-4


Cl-  in  the  final  mixture   is =(4.5  x10^-5 /0.085)  -  1.342  x10^-5= 5.16 x10^-4
4 0
4 years ago
Read 2 more answers
If He gas has an average kinetic energy of 4310 J/mol under certain conditions, what is the root mean square speed of O2 gas mol
Free_Kalibri [48]

Answer:

The root mean square speed of O2 gas molecules is

<u>519.01 m/s</u>

<u></u>

Explanation:

The root mean square velocity  :

v_{rms}=\sqrt{\frac{3RT}{M}}

K.E_{avg}=\frac{3}{2}RT

K.E =\frac{1}{2}mv_{rms}^{2}

Molar mass , M

For He = 4 g/mol

For O2 = 2 x 16 = 32 g/mol

O2 = 32/1000 = 0.032 Kg/mol

First calculate the temperature at which the K.E of He is 4310J/mol

K.E of He =

K.E_{avg}=\frac{3}{2}RT

T=\frac{2(K.E)}{3(R)}

K.E of He = 4310 J/mol

T=\frac{2(4310J/mol)}{3(8.314J/Kmol)}

T=345.60K

<u>Now , Use Vrms to calculate the velocity of O2</u>

v_{rms}=\sqrt{\frac{3(8.314J/Kmol)(345.60K)}{0.032Kg/mol}}

v_{rms}=\sqrt{\frac{8619.9552}{0.032}}

v_{rms}=\sqrt{26935.001}

v_{rms}=519.01m/s

6 0
4 years ago
Why has diamond has a high melting point
expeople1 [14]
Well since covalent bonds are strong and diamonds contains a lot of covalent bonds, it makes the diamond's melting point and boiling point very high.

6 0
3 years ago
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