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polet [3.4K]
3 years ago
9

Label the following as a pure substance or a mixture.

Chemistry
2 answers:
Zigmanuir [339]3 years ago
6 0

Answer: a mixture

Explanation:

Snezhnost [94]3 years ago
5 0

Answer:

b

Explanation:

can you help ,meeeeee

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The amount of force needed to keep a 10 kg box moving at a constant
boyakko [2]

Answer:

ON

Explanation:

Frictional force is a force that opposes the motion of body. It is because of friction that motion can be controlled and even walking is made possible.

Now, on a frictionless surface, there is no opposition to motion. Therefore, to keep the body moving there is no force required.

  • If surface lacks friction, motion will continue perpetually without any hinderance.
5 0
4 years ago
What is the density of ammonia gas, nh3, at 31°c and 751 mmhg?
solmaris [256]
First, we will use the general gas formula to get the number of moles.
PV = nRT where:
P is the pressure of gas = 751 mmHg = 100125.096375 Pascal
V is the volume = 1 liter = 0.001 m^3
n is the number of moles we want to calculate
R is the gas constant = <span>8.314 J/(K. </span>mol<span>)
T is the temperature = 31 degrees celcius = </span>304.15 degree kelvin

Substitute in the above equation to get the number of moles as follows:
100125.096375 * 0.001 = n * 8.314 * 304.15
n = 0.039595 moles

Now, we will use the number of moles to get the mass as follows:
number of moles = mass / molar mass
mass = number of moles * molar mass
number of moles = 0.039595 moles
molar mass of ammonia (NH3) = 14 + 3(1) = 17 grams
Substitute to get the mass as follows:
mass = 0.039595 * 17 = 0.673122 grams

Last step is to get the density as follows:
density = mass / volume
mass = 0.673122 grams
volume = 1 liter
density = 0.673122 / 1 = 0.673122 grams/liter = <span>0.000675 kg/L</span>



8 0
3 years ago
The pH of a 0.15 M butylamine, C&amp;H3NH2 solution is 12.0 at 25°C. Calculate the dissociation
Dmitrij [34]

The dissociation  constant of the base : 7.4 x 10⁻⁴

<h3>Further explanation</h3>

Butylamine, C4H9NH2 Is A Weak Base

Kb is the dissociation  constant of the base.​

LOH (aq) ---> L⁺ (aq) + OH⁻ (aq)  

\rm Kb=\dfrac{[L][OH^-]}{[LOH]}

[OH⁻] for weak base can be formulated :

\tt [OH^-]=\sqrt{Kb.M}

pH of solution : 12

pH+pOH=14, so pOH :

14-12 = 2, then :

\tt [OH^-]=10^{-pOH}\\\\(OH^-]=10^{-2}

the the dissociation  constant (Kb) =

\tt 10^{-2}=\sqrt{Kb.0.15}\\\\10^{-4}=Kb\times 0.15\\\\Kb=\dfrac{10^{-4}}{0.15}=6.6\times 10^{-4}

Or you can use from ICE method :

C4H9NH2(aq) + H2O(l) ⇌ C4H9NH3+(aq) + OH-(aq)

0.15

x                                                x                        x

0.15-x                                        x                        x

\tt Kb=\dfrac{x^2}{0.15-x}\rightarrow x=[OH^-]\\\\Kb=\dfrac{10^{-4}}{0.15-10^{-2}}=7.14\times 10^{-4}

6 0
3 years ago
Imagine a drop of oil in water. If you add a surfactant, explain how the surfactant molecules organize themselves around the oil
Annette [7]
<span>the hydrophobic portions would surround the oil and hydrophilic would surround the water... for either</span>
8 0
4 years ago
Read 2 more answers
Identify the reaction type:
WARRIOR [948]

Answer:

The reaction type is Synthesis

8 0
3 years ago
Read 2 more answers
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